Two triangles are said to be <u>congruent</u> if they have <em>similar</em> properties. Thus the required <u>options</u> to complete the <em>paragraph proof</em> are:
a. angle 1 is <u>congruent</u> to angle 2.
b. <em>alternate</em> angles are <u>congruent</u> if two parallel lines are cut by a <em>transversal</em>.
c. =
The <em>similarity property</em> of two or more shapes implies that the <u>shapes</u> are congruent. Thus they have the <em>same</em> properties.
From the given <u>diagram</u> in the question, it can be deduced that
ΔABC ≅ ΔABE (<em>substitution</em> property of equality)
Given that EA is <u>parallel</u> to BD, then:
i. <2 ≅ <3 (<em>corresponding</em> angle property)
ii. <1 ≅ < 4 (<em>alternate</em> angle property)
Thus, the required options to complete the <em>paragraph proof</em> are:
- Angle 1 is <em>congruent</em> to angle 2.
- Alternate angles are <u>congruent</u> if two parallel lines are cut by a <em>transversal</em>.
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For more clarifications on the properties of congruent triangles, visit: brainly.com/question/1619927
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