Answer:

Step-by-step explanation:
Given
See attachment
Required
Vertical length / Horizontal length
From the attachment, we have:
--- the vertical length of the larger triangle
and
--- the horizontal length of the larger triangle
So, the ratio is:



Divide by 2

Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
The answer is $25.35
6.96× 3= 20.85
20.85+ 4.50= $25.35
Answer:

Step-by-step explanation:
In the given figure, PQRS is a rhombus and SRM is an equilateral triangle.
We are also given that SN⊥RM and that ∠PRS = 55°.
And we want to find the measure of ∠QSN.
Remember that since PQRS is a rhombus, the angles formed by its diagonals are right angles. Let the intersection point of the diagonals be K. Therefore:

Now, RKS is also a triangle. The interior angles of all triangles must be 180. Thus:

Substitute in known values:

Solve for ∠KSR:

Since SRM is an equilateral triangle, this means that:

Note that RNS is also a triangle. Therefore:

Substitute in known values:

So:

∠QSN is the addition of the two angles:

Therefore:
