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gavmur [86]
3 years ago
6

Tim, Paco, Maria, and Jenny are standing in line for lunch. Jenny is standing between Paco and Maria, and Paco’s position in lin

e is an odd number. Tim is not standing on either end of the line, and he is in front of Jenny. Use the process of elimination to make a table of each friend’s position in line.What is the order of people standing in line?
Mathematics
1 answer:
zubka84 [21]3 years ago
4 0
Tim will not be in positions 1 or 4, as 1 and 4 represent the ends of the line.
Jenny cannot be in positions 1 or 4, as she is between two people.
Paco will not be in positions 2 or 4, as he is only in an odd numbered position.

Based on this, you can conclude that Maria will be in position 4, as none of the other three can be at position 4.
Paco will be in position 1, as Tim and Jenny cannot be at position 1. 
The two positions left are 2 and 3. We'll assume that 1 represents the front of the line. Since Tim has to be in front of Jenny, he will take the position with the lower number, which is 2. This leaves Jenny with 3.

In order from 1 to 4, the line is as follows:

Paco, Tim, Jenny, Maria
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See attachment

Required

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3 years ago
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we reject  H₀

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And Test hypothesis is:

H₀         Null hypothesis           μ   =  μ₀

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6 0
3 years ago
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Mia and mai want to to rent a canoe at the boat house on the river. it cost $6.95 to rent a canoe for 1 hour. the price per hour
stiv31 [10]
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7 0
4 years ago
Heya!
nataly862011 [7]

Answer:

m\angle QSN=65^\circ

Step-by-step explanation:

In the given figure, PQRS is a rhombus and SRM is an equilateral triangle.

We are also given that SN⊥RM and that ∠PRS = 55°.

And we want to find the measure of ∠QSN.

Remember that since PQRS is a rhombus, the angles formed by its diagonals are right angles. Let the intersection point of the diagonals be K. Therefore:

m\angle RKS=90^\circ

Now, RKS is also a triangle. The interior angles of all triangles must be 180. Thus:

m\angle RKS+m\angle KSR+m\angle SRK=180

Substitute in known values:

90+55+m\angle KSR=180

Solve for ∠KSR:

m\angle KSR+145=180\Rightarrow m\angle KSR=35^\circ

Since SRM is an equilateral triangle, this means that:

m\angle SRM=m\angle RMS=m\angle MSR=60^\circ

Note that RNS is also a triangle. Therefore:

m\angle SRM+m\angle RNS+m\angle NSR=180

Substitute in known values:

60+90+m\angle NSR=180

So:

m\angle NSR+150=180\Rightarrow m\angle NSR=30^\circ

∠QSN is the addition of the two angles:

m\angle QSN=m\angle KSR+m\angle NSR

Therefore:

m\angle QSN=35+30=65^\circ

4 0
3 years ago
Read 2 more answers
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