Answer:
<h2>
Haploid=13</h2><h2>
triploid=39 </h2><h2>
tetraploid=52</h2><h2>
trisomic=14 </h2><h2>
monosomic=12</h2>
Explanation:
Given;
A species with a diploid number of 26, so 26= 2n ( a diploid cell),
so in haploid condition, chromosome number becomes half (13 in this case). triplod is when 2n + n, and 2n +2n ( tetploid). Trisomy and monosomy is the addition or deletion of a sinlge chromosome of a sinlge set .
Haploid=13, one chromosome from each pair of chromosome set,
triploid=39 (13× 3); diploid+ n( 3n)
tetraploid=52 (13× 4) 4n
trisomic=14 (13+1) ; n+1
monosomic=12 (13-1); n-1
Answer:
Explanation:
A way you can use celery stalks to demonstrate the conditions with loss or gain of turgor pressure, is by setting us the same situation with water. I. You could possibly make a chart with how the celery could change. II. Testing the different out comes of the celery changing and what it has done and if it matches the hypothesis. III. The type of data you could conduct would be is seeing the height, length, and width. As wellas trying to see how much celery would soak up. IV. A possible conclusion of that experiment would be that the celery stalks would all expand expect for the one not in any water and it all would possibly start to grow into more than one celery and sprout. H2OH2O
Answer:
A lethal mutation, thereby the resulting phenotype is not observed
.
Explanation:
Lethal mutations are the result of genomic changes that may be lethal in certain conditions. In genetic research, this type of mutation has shown to be very useful in analyzing gene function (i.e., genes whose protein products are key for the survival of the organism in question), and they are perfect gene markers. In bacteriophages, for example, temperature-sensitive mutants of phage T4 that can not grow at temperatures higher 42°C have been identified (Edgar & Lielausis 1964).
Citation:
R. S. Edgar, & I. Lielausis (1964). Temperature-sensitive mutants of bacteriophage T4D: their isolation and genetic characterization. Genetics, 49(4), 649.
