Answer: 1/4
Explanation:
Firstly, in order for both parents to be type A and have children with type o blood, their blood types must both be Ao. Since o is a recessive blood type, a punnett square shows there is a 25% chance any child of theirs will have type o blood. If neither parent is color blind and they have a son who is, it implies that the mother is a carrier of colorblindness and has the genotype XᴮXᵇ. If you do a punnett square of the not colorblind father (XᴮY) and the mother, it shows that a daughter would have a 0% chance of being colorblind. Therefore colorblindess is irrelevent, since there is no possibility of the daughter not having normal color vision. In conclusion, there's a 25% chance she will have type o blood and not be colorblind, since the other 75% chance would be having type A blood and not being colorblind.
Answer:
For your body to cool down one method is to sweat.
Explanation: Your sweat glands release sweat, which cools your skin as it evaporates. This helps lower your internal temperature
Plant cell. it an keep its shape beacuse it has a cell wall. it might have chlorophyll in it which allows photosynthesis
Answer: is seen below
Explanation:
Termination will not take place if the strings of A nucleotides following an inverted repeat of rho- independent termination ( which forms an hairpin structure)were deleted. Although, RNA polymerase may pause briefly at the hairpin, the presence of A- U base pairs is needed to destabilize the DNA - RNA interaction and to end transcription. If the string A nucleotides is not present, then transcription of RNA polymerase will continue.
The mother because it is an x-linked trait and the boy received a y from his father so therefore he could only get the x from his mother.
