Answer:
<em><u>0.328 kg</u></em>
Explanation:
Given data:
Lattice energy of Potassium nitrate (KNO3) = -163.8 kcal/mol
Heat of hydration of KNO3 = -155.5 kcal/mol
Heat to absorb by KNO3 = 113kJ
To find:
Mass of KNO3 to dissolve in water = ?
Solution:
Heat of solution = Hydration energy - Lattice energy
= -155.5 -(-163.8)
= 8.3 kcal/mol
We already know,
1 kcal/mol = 4.184 kJ/mole
Therefore,
= 4.184 kJ/mol x 8.3 kcal/mol
= 34.73 kJ/mol
Now, 34.73 kJ of heat is absorbed when 1 mole of KNO3 is dissolved in water.
For 113 kJ of heat would be
= 113/34.73
= 3.253 moles of KNO3
Molar mass of KNO3 = 101.1 g/mole
Mass of KNO3 = Molar mass x moles
= 101.1 g/mole x 3.253
= 328.87 g
= 0.328 kg
<em><u>328.8 g potassium nitrate has to dissolve in water to absorb 113 kJ of heat.</u></em>
Answer:
48.5 kJ
Explanation:
Let's consider the sublimation of carbon dioxide at its sublimation temperature, that is, its change from the solid to the gaseous state.
CO₂(s) → CO₂(g)
The molar mass of carbon dioxide is 44.01 g/mol. The moles corresponding to 66.0 g are:
66.0 g × (1 mol/44.01 g) = 1.50 mol
The heat of sublimation for carbon dioxide is 32.3 kJ/mol. The heat required to sublimate 1.50 moles of carbon dioxide is:
1.50 mol × (32.3 kJ/mol) = 48.5 kJ
Answer: Mass of hydrogen produced is 0.0376 g.
Explanation:
The reaction equation will be as follows.

Now, formula for total pressure will be as follows.

Hence, 
= 755 mm Hg - 42.23 mm Hg
= 712.77 mm Hg

= 0.937 atm
Now, we will calculate the moles of
as follows.


n =
mol
= 0.0187 mol
Therefore, mass of
will be calculated as follows.

= 0.0376 g
Thus, we can conclude that mass of hydrogen produced is 0.0376 g.