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Mrrafil [7]
3 years ago
7

A sample has a hydrogen ion concentration of 1 × 10−2. What happens if the hydrogen ion concentration increases? The acidity dec

reases. The pH decreases. The hydroxide ion concentration increases. The solution becomes more basic.
Chemistry
2 answers:
Montano1993 [528]3 years ago
8 0

Answer : The correct option is, The pH decreases.

Explanation :

As we know that,

pH : It is defined as the negative logarithm of hydrogen ion concentration.

Mathematically it is represented as :

pH=-\log [H^+]

According to the question, when the concentration of hydrogen ion increases then the value of pH decreases and the acidity of the solution also increases that means the solution is more acidic in nature.

Hence, if the hydrogen ion concentration increases, the pH decreases.

Marta_Voda [28]3 years ago
5 0

Answer:

The pH decreases

Explanation:

Hello,

pH is mathematically defined via:

pH=-log([H^{+} ])

Since at the beginning, the concentration of hydride ion is 1e-2M, the pH is:

pH=-log(1x10^{-2} )=2.0

If it is increased, lets suppose to 1.1e-2, the new pH turns out into:

pH=-log(1.1x10^{-2} )=1.96

So the pH decreases, which means that the acidity increases as well.

Best regards.

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Potassium nitrate has a lattice energy of -163.8 kcal/mol and a heat of hydration of -155.5 kcal/mol. How much potassium nitrate
Amanda [17]

Answer:

<em><u>0.328 kg</u></em>

Explanation:

Given data:

Lattice energy of Potassium nitrate (KNO3) = -163.8 kcal/mol

Heat of hydration of KNO3 = -155.5 kcal/mol

Heat to absorb by KNO3 = 113kJ

To find:

Mass of KNO3 to dissolve in water = ?

Solution:

Heat of solution = Hydration energy - Lattice energy

                           = -155.5 -(-163.8)

                           = 8.3 kcal/mol

We already know,

1 kcal/mol = 4.184 kJ/mole

Therefore,

= 4.184 kJ/mol x 8.3 kcal/mol

= 34.73 kJ/mol

Now, 34.73 kJ of heat is absorbed when 1 mole of KNO3 is dissolved in water.

For 113 kJ of heat would be

= 113/34.73

= 3.253 moles of KNO3

Molar mass of KNO3 = 101.1 g/mole

Mass of KNO3 = Molar mass x moles

                        = 101.1 g/mole  x  3.253

                       = 328.87 g

                       = 0.328 kg

<em><u>328.8 g potassium nitrate has to dissolve in water to absorb 113 kJ of heat.</u></em>      

8 0
4 years ago
Calculate the amount of heat required to completely sublime 66.0 gg of solid dry ice (CO2)(CO2) at its sublimation temperature.
atroni [7]

Answer:

48.5 kJ

Explanation:

Let's consider the sublimation of carbon dioxide at its sublimation temperature, that is, its change from the solid to the gaseous state.

CO₂(s) → CO₂(g)

The molar mass of carbon dioxide is 44.01 g/mol. The moles corresponding to  66.0 g are:

66.0 g × (1 mol/44.01 g) = 1.50 mol

The heat of sublimation for carbon dioxide is 32.3 kJ/mol. The heat required to sublimate 1.50 moles of carbon dioxide is:

1.50 mol × (32.3 kJ/mol) = 48.5 kJ

7 0
3 years ago
I'm kinda in a rush but take your time!Thx! 1.What was Henri Becquerel studying when he accidentally discovered radioactivity?
zzz [600]
1.C
2.B
3.B
4.D
Are the answers I got
4 0
3 years ago
C3H8(g)+ 5O2(g) 3C02(g) + 4H2O (g)
adelina 88 [10]

Answer:

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Explanation:

6 0
3 years ago
find the mass of h2 produced Binary compounds of alkali metals and hydrogen react with water to produce H2(g). The H2H2 from the
scZoUnD [109]

Answer: Mass of hydrogen produced is 0.0376 g.

Explanation:

The reaction equation will be as follows.

NaH(aq) + H_{2}O(l) \rightarrow H_{2}(g) + NaOH(aq)

Now, formula for total pressure will be as follows.

  P_{total} = P_{H_{2}} + P_{H_{2}O}

Hence,    P_{H_{2}} = P_{total} - P_{H_{2}O}

                            = 755 mm Hg - 42.23 mm Hg

                            = 712.77 mm Hg

P_{H_{2}} = \frac{712.77 \times 1 atm}{760 mm Hg}

             = 0.937 atm

Now, we will calculate the moles of H_{2} as follows.

   P_{H_{2}}V = nRT

   0.937 atm \times 0.505 L = n \times 0.0821 \times 308.15 K

      n = \frac{0.473}{25.29} mol

         = 0.0187 mol

Therefore, mass of H_{2} will be calculated as follows.

        m_{H_{2}} = \frac{0.0187 mol \times 2.0158 g}{1 mol}

                   = 0.0376 g

Thus, we can conclude that mass of hydrogen produced is 0.0376 g.

7 0
3 years ago
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