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uranmaximum [27]
3 years ago
5

Why are bones hard and muscles soft

Chemistry
1 answer:
Maurinko [17]3 years ago
3 0

Answer:

Muscles need stretchting and be able to contract and release while bones need to be hard in order to be the framework for the body and protect vital organs and the nervous system.

Explanation:

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Classify each of the following elements as
tino4ka555 [31]

Answer:Silicon is neither metal nor non-metal; it's a metalloid, an element that falls somewhere between the two. The category of metalloid is something of a gray area, with no firm definition of what fits the bill, but metalloids generally have properties of both metals and non-metals.

Explanation:

5 0
3 years ago
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dem82 [27]

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4 0
3 years ago
What is the maximum mass of s8 that can be produced by combining 87.0 g of each reactant? 8so2+16h2s=3s8+16h20?
zhenek [66]
The balanced chemical reaction is expressed as:

<span>8SO2 + 16H2S = 3S8 + 16H2O

We are given the initial amount of the reactants. From there, we determine the limiting reactant. We do as follows:

87.0 g SO2 ( 1 mol / 64.07 g ) = 1.36 mol SO2 ( 16 mol H2S / 8 mol SO2 ) = 2.72 mol H2S
87.0 g H2S ( 1 mol / 34.08 g ) = 2.55 mol H2S ( 8 mol SO2 / 16 mol H2S ) = 1.28 mol SO2

Therefore, the limiting reactant would be H2S. We calculate the maximum amount of S8 that can be produced from the amount of H2S.

2.55 mol H2S ( 3 mol S8 / 16 mol H2S ) ( 256.48 g / 1 mol ) = 122.63 g S8</span>
6 0
3 years ago
If 309 grams of potassium combines with 228 g chlorine gas, how many grams of the single product will be formed? What are the LR
lisov135 [29]

The amount of KCl that would be formed will be 478.8 grams

<h3>Stoichiometric calculations</h3>

From the equation of the reaction, the mole ratio of K to Cl_2 is 2:1.

Mole of 309 g potassium = 309/39 = 7.92 moles

Mole of 228 g Cl2 = 228/71 = 3.21 moles

Thus, potassium is in excess while Cl2 is limiting.

Mole ratio of Cl2 and KCl = 1:2

Equivalent mole of KCl = 3.21 x 2 = 6.42 moles

Mass of 6.42 moles KCl = 6.42 x 74.55 = 478.8 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1

4 0
2 years ago
When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO3 ( s ) + 2
BigorU [14]

Answer:

19.7 g of CaCl₂ are produced in the reaction

Explanation:

In this excersise we need to know the limiting reactant in order to determine the mass produced of a one of the products

The reaction is: CaCO₃ (s) + 2HCl (aq) → CaCl₂(aq) + H₂O (l) + CO₂(g)

First of all we must find the limiting reactant. For that purpose, we convert the mass of reactants to moles

25 g / 100.08 g/mol = 0.249 moles of carbonate

13 g / 36.45 g/mol = 0.357 moles of HCl

We work with the stoichiometry of the reaction:

1 mol of carbonate reacts with 2 moles of hydrochloric

Then, 0.249 moles of carbonate must react with (0.249 . 2) /1 = 0.498 moles of HCl (We do not have enough HCl, so this is the limtiing reactant)

We work with the stoichiometry reactant / product

2 moles of HCl can produce 1 mol of CaCl₂

Therefore 0.357 moles of HCl must produce (0.357 .1) / 2  = 0.178 moles of chloride.

We convert the moles to mass → 0.178 mol . 110.98 g /1mol = 19.7g

5 0
3 years ago
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