Answer:
Option A - When |ΔHsolute| > |ΔHhydration|
Explanation:
A solution is defined as a homogeneous mixture of 2 or more substances that can either be in the gas phase, liquid phase, solid phase.
The enthalpy of solution can either be positive (endothermic) or negative (exothermic).
Now, we know that enthalpy is amount of heat released or absorbed during the dissolving process at constant pressure.
Now, the first step in thus process involves breaking up of the solute. This involves breaking up all the intermolecular forces holding the solute together. This means that the solute molecules are separate from each other and the process is always endothermic because it requires energy to break interaction. Thus;
The enthalpy ΔH1 > 0.
Thus, the enthalpy of the solute has to be greater than the enthalpy of hydration.
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Answer:
The solution becomes colorless and a light blue precipitate is formed.
Explanation:
When sodium hydroxide is added to copper(II) nitrate solution, a precipitate of copper(II) hydroxide is formed.
The solution gradually becomes colorless as the light blue precipitate appears.
The reaction is complete (enough sodium hydroxide has been added) when the blue color of the solution completely disappears.
The equation of the reaction is;
Cu(NO3)2(aq) + 2NaOH(aq) → Cu(OH)2(s) + 2NaNO3(aq)
Answer:
Kr has one more electron than br and so, the nuclear charge increase, which means the nuclear attraction between the nucleus and outer most electron will increase and so will be harder to remove the electron from Kr than Br, so Kr has higher 1st ionisation.
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Explanation:
where are the chemical reactions and their properties to match ?????????
