Does changing the compound inequality x > −3 and x < 3 from “and” to “or” change the solution set

1 answer:

3 0

Yes. this changes it because "and" means that the solution is definately between those two. Using "or" means that the number can either be less than 3 infinitely or greater than -3 infinitely. <span />

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The sum of a number and two times a smaller number is 62. Three times the bigger number exceeds the smaller number by 116. The b

Korvikt [17]

<span>x + 2y = 62
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put the system of linear equations into standard form
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x + 2y = 62
3x - y = 116
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</span>

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solve the inequality $\frac{29}{289z<\frac{16}{161}z$. try to solve the problem without doing a lot of messy computations!

Lesechka [4]

The solution to the given inequality as represented in the task content are; z < - 1.00485413 OR z > 1.00485413.

<h3>What is the solution to the given inequality?</h3>

It follows from the task content that the solution of the given inequality; ( 29 / 289z ) < ( 16 / 161 ) z is to be determined.

Since the given inequality is;

( 29 / 289z ) < ( 16 / 161 ) z

By cross multiplication; we have;

161 × 29 < ( 16z × 289z )

( 161 × 29 ) / ( 16 × 289 ) < z²

1.00973183 < z²

Therefore;

1.00485413 < z. OR. -1.00485413 > z.

Ultimately, z < - 1.00485413 OR z > 1.00485413.