I think that the answer is 16
Answer:
Option D, 2x^2y(x - 1)(x^2 + x + 1)
Step-by-step explanation:
<u>Step 1: Factor</u>
2x^5y - 2x^2y
2x^2y(x^3 - 1)
<em>2x^2y(x - 1)(x^2 + x + 1)</em>
<em />
Answer: Option D, 2x^2y(x - 1)(x^2 + x + 1)
Answer:
23x2+8xy−57y2
Step-by-step explanation:
(5x)(5x)+(5x)(7y)+(−7y)(5x)+(−7y)(7y)+−2x2+8xy+−8y2
=25x2+35xy+−35xy+−49y2+−2x2+8xy+−8y2
Combine Like Terms:
=25x2+35xy+−35xy+−49y2+−2x2+8xy+−8y2
=(25x2+−2x2)+(35xy+−35xy+8xy)+(−49y2+−8y2)
=23x2+8xy+−57y2
Plz mark brainlest :)
2700 is the answer. You do 9 times 3 then add the 0s
If we use the place value chart, 10020 and 20010 will be further dissected based on place values. At first look, 20010 seems to have more tens and that is fact; but this method will show us that it is otherwise so follow the solution below carefully:
Employing PLACE VALUE CHART:
For 20010:
*10000 <--- Ten-thousands place.
*10000 <--- Ten-thousands place.
*10 <--- Tens place.
Add these numbers and you will get: 20010. 20010 has two ten-thousands place and one tens place.
For 10020
*10000 <--- Tens-thousands place.
*10 <--- Tens place.
*10 <--- Tens place.
Add these numbers and you will get: 10020. 10020 has one ten-thousands place and two tens place.
Therefore, there are more tens in 10020 than in 20010.
