If the measure of angle θ is 3π/4, the true statements are:
- sin(θ) = √2/2.
- The measure of the reference angle is 45°.
<h3>How to determine the true statements?</h3>
In Trigonometry, an angle with a magnitude of 3π/4 (radians) is equivalent to 135° (degrees) and it's found in the second quarter. Thus, we would calculate the reference angle for θ in second quarter as follows:
Reference angle = 180 - θ
Reference angle = 180 - 135
Reference angle = 45°.
Also, a terminal point for this angle θ is given by (-√2/2, √2/2) which corresponds to cosine and sine respectively. This ultimately implies that sin(θ) = √2/2.
tan(θ) = cos(θ)/sin(θ)
tan(θ) = [(-√2/2)/(√2/2)]
tan(θ) = -1
In conclusion, we can logically deduce that only options A and B are true statements.
Read more on terminal point here: brainly.com/question/4256586
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Complete Question:
If the measure of angle θ is 3π/4, which statements are true. Select all the correct answers.
A. sin(θ)=sqrt2/2
B. The measure of the reference angle is 45
C. The measure of the reference angle is 30
D. The measure of the reference angle is 60
E. cos(θ)=sqrt2/2
F. tan(θ)=1
Answer:
$112.80
Step-by-step explanation:
If he earns $0.235 per pack, and there are 480 packs, then our equation is:
0.235 x 480 = $112.80
A=18
Explanation:multiply both sides by 3 to get rid of the fraction so u are left with a=18
Answer:
20b^2
Step-by-step explanation:
Answer:
C. 178−−−√ m
Step-by-step explanation:
Given the following :
v = final velocity (in m/s)
u = initial velocity (in m/s)
a = acceleration (in m/s²)
s = distance (in meters).
Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters
Using the 3rd equation of motion :
v^2 = u^2 + 2as
v^2 = 8^2 + 2(3)(19)
v^2 = 64 + 114
v^2 = 178
Take the square root of both sides :
√v^2 = √178
v = √178
