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bekas [8.4K]
3 years ago
5

The dimensions of a cube are doubled. The volume of the enlarged cube is how many times the volume of the original cube?

Mathematics
2 answers:
Tom [10]3 years ago
8 0
4 times due to the fact that when it is doubled you will have to multiply by two.
Elza [17]3 years ago
5 0
The volume is multiplied by 8. For example if you have a 1x1x1 cube the volume is 1. If you have a 2x2x2 cube the volume is 8. If you have a 4x4x4 the volume is 64.
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Solve for x. x/2+1= √3
podryga [215]
X=1.464102
Simplifies to: (1/2x)+1=1.732051

Step 1: Subtract 1 from both sides.
1/2x + 1 -1=1.732051-1
(1/2x)=0.732051

Step 2: Multiply both sides by 2
2*(1/2x) = (2) * (0.732051)
X=1.464102
7 0
3 years ago
10 points...............
Alisiya [41]
I think the one that's gray that's the correct answer.Hope this helps! ;)
7 0
3 years ago
Read 2 more answers
Can somebody help me answer these plz?
Rus_ich [418]

I think the answer would be 57.75

6 0
3 years ago
Can someone please help me with this problem asap? Thanks!! :))
ivolga24 [154]

Answer: \$4.34

Step-by-step explanation:

We have the following information:

Fredburguer F, milkshake M and an order of fries f costs \$3.72:

F+M+f=\$3.72 (1)

One Fredburguer is equal to a milkshake plus orders of fries:

F=M+2f (2)

Three milshakes is equal to a Fredburguer plus an order of fries:

3M=F+f (3)

And we are asked: If we have a Fredburguer, a milkshake and two orders of fries, how much do we have to pay?

F+M+2f=x (4)

Well with the first three equations we have a system of equations to solve. Let's begin by isolating F from (3):

F=3M-f (5)

Making (2)=(5):

M+2f=3M-f (6)

Isolating f:

f=\frac{2}{3}M (7)

Substituting (7) in (2):

F=M+2(\frac{2}{3}M) (8)

Isolating F:

F=\frac{7}{3}M (9)

Substituting (7) and (9) in (1):

\frac{7}{3}M+M+\frac{2}{3}M=\$3.72 (10)

Isolating M:

M=\$0.93 (11) This is the cost of a Milkshake

Substituting (11) in (7):

f=\frac{2}{3}\$0.93 (12)

f=\$0.62 (13) This is the cost of an order of frieds

Substituting (11) in (9):

F=\frac{7}{3}\$0.93 (14)

F=\$2.17 (15) This is the cost of a Fredburguer

Substituting (11), (13) and  (15) in (4):

\$2.17+\$0.93+2(\$0.62)=x (16)

Finally:

x=\$4.34 This is the cost of a Fredburguer, a milkshake and two orders of fries

8 0
3 years ago
What is the conditional relative frequency of selling an item marked 50% off, provided the item sold is item 2?
sukhopar [10]

Answer:

Conditional relative frequency = 0.67

Step-by-step explanation:

               50% off        Buy 1, get 1 free      Total

Item 1         12                       8                      20

Item 2         20                      10                     30

Total           32                      18                     50

Condition relative frequency table:

               50% off        Buy 1, get 1 free      Total

Item 1         \frac{12}{20}=0.6             \frac{8}{20}=0.4            \frac{20}{20}=1

Item 2        \frac{20}{30}=0.67           \frac{10}{30}=0.33          \frac{30}{30}=1

Total            \frac{32}{50}=0.64           \frac{18}{50}=0.36          \frac{50}{50}=1

Therefore, conditional relative frequency of selling an item marked 50% off, provided the item sold is item 2 = 0.67

8 0
3 years ago
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