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navik [9.2K]
3 years ago
8

The weight, in grams, of eight different kiwis was used to create the box plot shown above. Which of the sets of numbers below m

atches the given box plot?
A.
Weights of Kiwis: 68, 73, 75, 75, 76, 76, 78, 80

B.
Weights of Kiwis: 68, 70, 75, 75, 75, 76, 77, 80

C.
Weights of Kiwis: 68, 72, 75, 75, 76, 76, 77, 80

D.
Weights of Kiwis: 68, 70, 72, 75, 75, 76, 78, 80

Mathematics
2 answers:
iris [78.8K]3 years ago
4 0
The answer is 75 because it explain it
Basile [38]3 years ago
3 0

Answer:

Step-by-step explanation:

The answer is d because 75 is the medain of the kiwi fruit

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Jasmin, Quinn, and Maddy are rock climbing. Jasmin is 42 ½ feet below Quinn. Maddy is 67 ¾ feet above Jasmin. What is Maddy's po
ladessa [460]

Answer:

25\frac{1}{4} feet

<em />

Step-by-step explanation:

Given

Maddy = 67\frac{3}{4} above Jasmin

Jasmin = 42\frac{1}{2} below Quinn

Required

Determine Maddy's position relative to Quinn's

From the given parameter, one can easily deduce that Quinn is in between Maddy and Jasmin (See attachment)

Using the attachment as a point of reference;

z = 67\frac{3}{4}

x = 42\frac{1}{2}

The relationship between x, y and z is

z = y + x

Make y the subject of formula

y = z - x

Substitute the values of z and x

y = 67\frac{3}{4} - 42\frac{1}{2}

Convert to improper fractions

y = \frac{271}{4} - \frac{85}{2}

Take LCM

y = \frac{271 - 170}{4}

y = \frac{101}{4}

y = 25\frac{1}{4}

<em>Hence; Maddy's position relative to Quinn's is </em>25\frac{1}{4}<em> feet</em>

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Step-by-step explanation:

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Answer:

20) \displaystyle [4, 1]

19) \displaystyle [-5, 1]

18) \displaystyle [3, 2]

17) \displaystyle [-2, 1]

16) \displaystyle [7, 6]

15) \displaystyle [-3, 2]

14) \displaystyle [-3, -2]

13) \displaystyle NO\:SOLUTION

12) \displaystyle [-4, -1]

11) \displaystyle [7, -2]

Step-by-step explanation:

20) {−2x - y = −9

{5x - 2y = 18

⅖[5x - 2y = 18]

{−2x - y = −9

{2x - ⅘y = 7⅕ >> New Equation

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\displaystyle \frac{-1\frac{4}{5}y}{-1\frac{4}{5}} = \frac{-1\frac{4}{5}}{-1\frac{4}{5}}

\displaystyle y = 1[Plug this back into both equations above to get the x-coordinate of 4]; \displaystyle 4 = x

_______________________________________________

19) {−5x - 8y = 17

{2x - 7y = −17

−⅞[−5x - 8y = 17]

{4⅜x + 7y = −14⅞ >> New Equation

{2x - 7y = −17

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\displaystyle \frac{6\frac{3}{8}x}{6\frac{3}{8}} = \frac{-31\frac{7}{8}}{6\frac{3}{8}}

\displaystyle x = -5[Plug this back into both equations above to get the y-coordinate of 1]; \displaystyle 1 = y

_______________________________________________

18) {−2x + 6y = 6

{−7x + 8y = −5

−¾[−7x + 8y = −5]

{−2x + 6y = 6

{5¼x - 6y = 3¾ >> New Equation

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\displaystyle \frac{3\frac{1}{4}x}{3\frac{1}{4}} = \frac{9\frac{3}{4}}{3\frac{1}{4}}

\displaystyle x = 3[Plug this back into both equations above to get the y-coordinate of 2]; \displaystyle 2 = y

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17) {−3x - 4y = 2

{3x + 3y = −3

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\displaystyle \frac{-y}{-1} = \frac{-1}{-1}

\displaystyle y = 1[Plug this back into both equations above to get the x-coordinate of −2]; \displaystyle -2 = x

_______________________________________________

16) {2x + y = 20

{6x - 5y = 12

−⅓[6x - 5y = 12]

{2x + y = 20

{−2x + 1⅔y = −4 >> New Equation

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\displaystyle \frac{2\frac{2}{3}y}{2\frac{2}{3}} = \frac{16}{2\frac{2}{3}}

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_______________________________________________

15) {6x + 6y = −6

{5x + y = −13

−⅚[6x + 6y = −6]

{−5x - 5y = 5 >> New Equation

{5x + y = −13

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14) {−3x + 3y = 3

{−5x + y = 13

−⅓[−3x + 3y = 3]

{x - y = −1 >> New Equation

{−5x + y = 13

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\displaystyle x = -3[Plug this back into both equations above to get the y-coordinate of −2]; \displaystyle -2 = y

_______________________________________________

13) {−3x + 3y = 4

{−x + y = 3

−⅓[−3x + 3y = 4]

{x - y = −1⅓ >> New Equation

{−x + y = 3

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\displaystyle 1\frac{2}{3} ≠ 0; NO\:SOLUTION

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12) {−3x - 8y = 20

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I am delighted to assist you anytime my friend!

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