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3 years ago

Help!!!!¡¡¡¡ i need help solving this it will increase my letter grade!!!!

Mathematics

1 answer:

Shtirlitz [24]3 years ago

6 0

Answer:

The answer is below⬇️⬇️

Step-by-step explanation:

f(x) = 3x+4

g(x) = 2x

h(x) = x²+x-2

g(hx) = 2(x²+x-2)

= 2x²+2x-4

f(g(hx))=3(2x²+2x-4)+4

=6x²+6x-12+4

=6x²+6x-8

g(f(g(hx)))=2(6x²+6x-8)

=12x²+12x-16

f(g(f(g(hx))))=3(12x²+12x-16)+4

=36x²+36x-48+4

=36x²+36x-44

h(f(g(f(g(hx)))))=(36x²+36x-44)²+36x²+36x-44-2

=1296x⁴+2592x³-1872x²-3168x+1936+36x²+36x-46

=1296x⁴+2592x³-1836x²-3132x+1890

f(h(f(g(f(g(hx))))))=3(1296x⁴+2592x³-1836x²-3132x+1890)+4

=3888x⁴+7776x³-5508x²-9396x+5674

h(f(h(f(g(f(g(hx)))))))=(3888x⁴+7776x³-5508x²-9396x+5674)²+3888x⁴+7776x³-5508x²-9396x+5674-2

=15116544x⁸+60466176x⁷+17635968x⁶-158723712x⁵-71663616x⁴+657591048x³-255531048x²-106635204x+32194276

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A line passes through the points (-8, 1) and (-1, 6). A second line passes through the points (-3,0) and (-8,-5). What is the po

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For the second line

$\begin{gathered} y=mx+b \\ m=\frac{-5-0}{-8+3}=\frac{-5}{-5}=1 \\ 0=1(-3)+b \\ b=3 \\ y=x+3 \end{gathered}$

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