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Ratling [72]
3 years ago
5

Help!!!!¡¡¡¡ i need help solving this it will increase my letter grade!!!!

Mathematics
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

The answer is below⬇️⬇️

Step-by-step explanation:

f(x) = 3x+4

g(x) = 2x

h(x) = x²+x-2

g(hx) = 2(x²+x-2)

= 2x²+2x-4

f(g(hx))=3(2x²+2x-4)+4

=6x²+6x-12+4

=6x²+6x-8

g(f(g(hx)))=2(6x²+6x-8)

=12x²+12x-16

f(g(f(g(hx))))=3(12x²+12x-16)+4

=36x²+36x-48+4

=36x²+36x-44

h(f(g(f(g(hx)))))=(36x²+36x-44)²+36x²+36x-44-2

=1296x⁴+2592x³-1872x²-3168x+1936+36x²+36x-46

=1296x⁴+2592x³-1836x²-3132x+1890

f(h(f(g(f(g(hx))))))=3(1296x⁴+2592x³-1836x²-3132x+1890)+4

=3888x⁴+7776x³-5508x²-9396x+5674

h(f(h(f(g(f(g(hx)))))))=(3888x⁴+7776x³-5508x²-9396x+5674)²+3888x⁴+7776x³-5508x²-9396x+5674-2

=15116544x⁸+60466176x⁷+17635968x⁶-158723712x⁵-71663616x⁴+657591048x³-255531048x²-106635204x+32194276

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Answer:

\boxed{\rm \: Volume_{(Cylinder)}  \approx \: 307.7 \: m {}^{3}  } ( \rm \: nearest \: tenth  )

Step-by-step explanation:

Given:

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Use the formulae of the volume of cylinder:

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  • height = 2 metres

Substitute the values onto the formulae in order to find out the volume:

\rm \: Volume_{(Cylinder)} = \pi(7) {}^{2} (2)

\rm \: Volume_{(Cylinder)} = \pi(49)(2)

\rm \: Volume_{(Cylinder)} = 98\pi

\rm \: Volume_{(Cylinder)} =  \: 98 \times 3.14

\rm \: Volume_{(Cylinder)} = 307.72  \: m {}^{3} \: (exact \: form)

\boxed{\rm \: Volume_{(Cylinder)}  \approx \: 307.7 \: m {}^{3} } \: ( \rm nearest \: tenth  )

<u>Hence,we can conclude that:</u>

The volume of the cylinder is approximately

307.7m³.

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