1. Simplify:

sqrt{361 } " align="absmiddle" class="latex-formula">

O A. 16
O B.17
O C. 18
OD. 19

Mathematics

2 answers:

quester [9]3 years ago

6 0

Answer:19

Step-by-step explanation:

Snowcat [4.5K]3 years ago

6 0

The answer is 19

19 x 19 = 361

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Which point best approximates the square root of 3?

ohaa [14]

It's B.

If $0$ , then it's also the case that $0$ , because multiplying any number $x$ by a number (in this case, also $x$ ) between 0 and 1 scales that number down.

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7 0

3 years ago

Read 2 more answers

How do I solve ln(x) + ln(5) = 2 ?

motikmotik

we'll use the same log cancellation rule, since this is pretty much the same thing as the other, just recall that ln = logₑ.

$\bf \textit{Logarithm Cancellation Rules}
\\\\
log_a a^x = x\qquad \qquad \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{a^{log_a x}=x}
\\\\\\
\textit{logarithm of factors}
\\\\
log_a(xy)\implies log_a(x)+log_a(y)
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
ln(x)+ln(5)=2\implies ln(x\cdot 5)=2\implies log_e(5x)=2
\\\\\\
e^{log_e(5x)}=e^2\implies 5x=e^2\implies x=\cfrac{e^2}{5}$

$\bf \\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
ln(x)-ln(5)=2\implies ln\left( \cfrac{x}{5} \right)=2\implies log_e\left( \cfrac{x}{5} \right)=2\implies e^{log_e\left( \frac{x}{5} \right)}=e^2
\\\\\\
\cfrac{x}{5}=e^2\implies x=5e^2$