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tigry1 [53]
4 years ago
13

You can model the population of a certain city between the years 1965 and 1995 by the radical function P(x)=75,000^3 SQRT x-1940

. Using this model, in what year was the population of that city 245,000?
a)1973
b)1975
c)1979
d)1970
Mathematics
1 answer:
inessss [21]4 years ago
7 0
The model is p(x) = 75,000 ∛(x - 1940)

Now use p(x) = 245,000 and solve for x

245,000 = 75,000 ∛(x - 1940) =

245,000 / 75,000 = ∛(x - 1940)

49/15 = ∛(x - 1940)

x - 1940 = [49/15]^3 = 34.86

x = 1940 + 34.86 = 1974.85

Then, the answer is 1975 (option b)
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Select the common ratio and the 4th term of the geometric series: 9, -6,4...
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The given geometric sequence has the common ratio, <u>r = -2/3</u>, and the value of the 4th term, <u>a₄ = -8/3</u>.

A geometric sequence is a special series where every term is the product of the previous term and a common ratio.

The first term of a geometric sequence is represented as a, the common ratio as r, and the n-th term as aₙ, which is calculated as, aₙ = a.rⁿ⁻¹.

In the question, we are asked to find the common ratio and the 4th term of the geometric sequence, 9, -6, 4, ........

The first term of the sequence, a = 9.

The second term of the sequence, a₂ = -6.

By the formula of the n-th term, aₙ = a.rⁿ⁻¹, we can show that:

a₂ = a.r²⁻¹.

Substituting the values, we get:

-6 = 9(r²⁻¹),

or, r²⁻¹ = -6/9,

or, r = -2/3.

Thus, the common ratio of the given geometric sequence is <u>-2/3</u>.

The 4th term can be calculated using the formula of the n-th term, aₙ = a.rⁿ⁻¹ as:

a₄ = a.r⁴⁻¹ = a.r³.

Substituting the values, we get:

a₄ = 9(-2/3)³,

or, a₄ = 9.(-8/27),

or, a₄ = -8/3.

Thus, the 4th term of the given geometric sequence is <u>-8/3</u>.

Learn more about a geometric sequence at

brainly.com/question/24643676

#SPJ1

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2 years ago
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