The standard form of hyperbola is:
(x-h)²/a²-(y-k)²/b²=1
center:(4,5)
Length of the horizontal transverse axis: 8-5=3=2a
thus
a=3/2
a²=9/4
b=2
b²=4
Hence the equation will be:
(x-4)²/(9/4)-(y-5)²/4=1
simplifying this we get:
[4(x-4)²]/9-(y-5)²/4=1
<span>In </span>mathematics<span>, a </span>matrix<span> <span>(plural </span></span>matrices) is a
rectangular array of numbers, symbols, or expressions, arranged in rows and
columns.
Given that
E = [ 1 2]
<span>A = | 3
0|</span>
<span> | 2
-1 |</span>
<span>2EA = 2 [1 2] | 3 0|</span>
<span> | 2 -1 |</span>
<span>2EA = [ 14
-4]</span>
<span> </span>
30-2 = 4x
28 = 4x
Divide both sides by 4 to eliminate the 4.
x=7
