Answer:
a) True
b) Parameter
Step-by-step explanation:
We are given the following in the question:
An accounting professor wants to know the average GPA of the students enrolled in her class.
Population:
- It is defined as the collection of all variables of interest.
- A sample of individuals of interest is drawn from a population.
For the given case
Individuals of interest:
Students enrolled in accounting class
Population of interest:
Students enrolled in accounting class
Characteristic of interest:
Average GPA of the students enrolled in her class.
a) The population is all students enrolled in the accounting class.
The given statement is true as it contains all the observation of all the individuals of interest.
b) The computed average GPA of all the students enrolled in the class is 3.29
Statistic is a descriptive measure that describes a sample where as a parameter is a measure that describes the population.
Since 3.29 is the average of all the students enrolled in her class that is the average GPA of population.
Thus, 3.29 is a parameter.
1.Convert 4 3/4 into an improper fraction: 19/4
2.Find a common denominator for 19/4 x 1/9:
36
3. Multiply numerators straight across.
Answer: 19/36
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer: 32
Step-by-step explanation:
48 - 16 is 32
Alright that sounds like a plan!!!
