Answer:
80.0456<
<81.1210
Step-by-step explanation:
-Given the mean, 
and 
, the confidence interval can be calculated using the formula:
#We substitute our values in the formula to solve for CI:
![=\bar x\pm z\times \frac{\sigma}{\sqrt{n}}\\\\=\bar y\pm z_{0.05}\times \frac{s}{\sqrt{72}}\\\\=80.5833\pm 1.645\times \frac{2.77369}{\sqrt{72}}\\\\=80.5833\pm0.5377\\\\=[80.0456,81.1210]](https://tex.z-dn.net/?f=%3D%5Cbar%20x%5Cpm%20z%5Ctimes%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C%5C%5C%3D%5Cbar%20y%5Cpm%20z_%7B0.05%7D%5Ctimes%20%5Cfrac%7Bs%7D%7B%5Csqrt%7B72%7D%7D%5C%5C%5C%5C%3D80.5833%5Cpm%201.645%5Ctimes%20%5Cfrac%7B2.77369%7D%7B%5Csqrt%7B72%7D%7D%5C%5C%5C%5C%3D80.5833%5Cpm0.5377%5C%5C%5C%5C%3D%5B80.0456%2C81.1210%5D)
Hence, the confidence interval lies between 80.0456 and 81.1210
Answer:
2
Step-by-step explanation:
just guessed
14 times 17 is 238.
I will draw an area model and add it to my answer.
Hope this helps!!!
Answer:
9,11
Step-by-step explanation:
let the numbers be x, x+2 (since consecutive odd integers have a difference of 2)
therefore;
x(x+2)= 99
x²+2x=99
I usually solve the sum like this,
we need to find the nearest square number ( number smaller than the number on the R.H.S)
here, it is 81, whose square root is 9. therefore the solution is 9
verification:
(9)²+2*9=99
81+18=99
99=99
hence, 9 is the solution. therefore the positive odd consecutive integers are
x=9
x+2=9+2= 11
verification:
9*11=99
99=99
L.H.S=R.H.S
Draw from (3, -1.5) to (-2, 6)
