For this case we have a square whose sides are known and equal to 60 ft.
We want to find the diagonal of the square.
For this, we use the Pythagorean theorem.
We have then:
Answer:
from home to second base it is about:
![d = 60\sqrt{2} feet](https://tex.z-dn.net/?f=d%20%3D%2060%5Csqrt%7B2%7D%20feet)
Answer:
Step-by-step explanation:
now the equation looks like
3-4Cos(x)=y
hmmm i'm wondering if you can figure it out from here??? it's the same as the other two.. plug in that
/2 .. can you? :)
Please find attached photograph for your answer.
Answer:
exact form 3/2 decimal form 1.5 mixed number form 1 1/2
Step-by-step explanation:
Answer:
![14\ pounds](https://tex.z-dn.net/?f=14%5C%20pounds)
Below is the procedure that was used to find the answer.
Step-by-step explanation:
Let be "e" the weight in pounds of the elephant and "c" the weight in pounds of the cat.
According to the information provided in the exercise, we know that The weight of an elephant is
times the weight of a cat. Based on this we can write the following equation:
![e=10^3c](https://tex.z-dn.net/?f=e%3D10%5E3c)
If the weight in pounds of the elephant is:
![e=14,000](https://tex.z-dn.net/?f=e%3D14%2C000)
We must substitute this value into the equation and then solve for "c" in order to find the weight in pounds of the cat.
Then we get:
![14,000=10^3c\\\\\frac{14,000}{10^3}=c\\\\c=14](https://tex.z-dn.net/?f=14%2C000%3D10%5E3c%5C%5C%5C%5C%5Cfrac%7B14%2C000%7D%7B10%5E3%7D%3Dc%5C%5C%5C%5Cc%3D14)