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Marat540 [252]
3 years ago
11

The length of a rectangle is represented by 7x+9, and its width is represented by 3x-2.

Mathematics
1 answer:
Monica [59]3 years ago
3 0

Answer:

hi

Step-by-step explanation:

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What is the slope of the line that passes through the points (-6, -8)(−6,−8) and (-14, 4) ?(−14,4)? Write your answer in simples
creativ13 [48]

Answer:

\huge\boxed{slope=-\dfrac{3}{2}}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (-6, -8) and (-14, 4).

Substitute

x_1=-6,\ y_1=-8,\ x_2=-14,\ y_2=4

m=\dfrac{4-(-8)}{-14-(-6)}=\dfrac{4+8}{-14+6}=\dfrac{12}{-8}=-\dfrac{12:4}{8:2}=-\dfrac{3}{2}

8 0
4 years ago
What is the image point of (9,5)(9,5) after a translation right 4 units and up 4 units?
skelet666 [1.2K]

Answer:

(13,9) I think

Step-by-step explanation:

I hope this helps and I hope I can get Brainliest! =)

8 0
3 years ago
Can somebody please help this is due very soon
joja [24]

Your answer is

  1.  Slope = -1.000/2.000 = -0.500
  2. x-intercept = 7/1 = 7.00000
  3. y-intercept = 7/2 = 3.50000

Step-by-step explanation:

4 0
3 years ago
Find the measure for &lt; MQX<br><br> 54<br> 59<br> 63<br> 65
vivado [14]
3x+39=5x+29
x=5
3(5)+39=54
5(5)+29=54
A) 54°
8 0
3 years ago
A sparkling-water distributor wants to make up 400 gal of sparkling water to sell for $8.00 per gallon. She wishes to mix mix th
Alex787 [66]

The sparkling-water distributor should use 160 gallons of $ 14 and 80 gallons of $ 3 and 160 gallons of $ 4.50

<em><u>Solution:</u></em>

Let "x" be the gallons of $ 14

Let "y" be the gallons of $ 3

Let "z" be the gallons of $ 4.5

<em><u>A sparkling-water distributor wants to make up 400 gal of sparkling water</u></em>

Therefore,

x + y + z = 400 --------- eqn 1

<em><u>She must use twice as much of the $4.50 water as the $3.00 water</u></em>

gallons of $ 4.5 = twice of gallons of $ 3

z = 2y --------- eqn 2

<em><u>A sparkling-water distributor wants to make up 400 gal of sparkling water to sell for $8.00 per gallon</u></em>

Therefore, we frame a equation as:

x \times 14 + y \times 3 + z \times 4.5 = 400 \times 8

14x + 3y + 4.5z = 3200 ----------- eqn 3

<em><u>Substitute eqn 2 in eqn 3</u></em>

14x + 3y + 4.5(2y) = 3200

14x + 3y + 9y = 3200

14x + 12y = 3200

Divide both sides by 2

7x + 6y = 1600 -------- eqn 4

<em><u>Substitute eqn 2 in eqn 1</u></em>

x + y + 2y = 400

x + 3y = 400

x = 400 - 3y ------- eqn 5

<em><u>Substitute eqn 5 in eqn 4</u></em>

7(400 - 3y) + 6y = 1600

2800 - 21y + 6y = 1600

15y = 1200

Divide both sides by 15

y = 80

<em><u>Substitute y = 80 in eqn 5</u></em>

x = 400 - 3(80)

x = 400 - 240

x = 160

<em><u>Substitute y = 80 in eqn 2</u></em>

z = 2(80)

z = 160

Thus she should use 160 gallons of $ 14 and 80 gallons of $ 3 and 160 gallons of $ 4.50

4 0
3 years ago
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