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2 years ago

Can somebody please help this is due very soon

Mathematics

1 answer:

joja [24]2 years ago

4 0

Your answer is

Slope = -1.000/2.000 = -0.500
x-intercept = 7/1 = 7.00000
y-intercept = 7/2 = 3.50000

Step-by-step explanation:

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A rope is cut into three pieces P, Q, and R the lengths of the pieces are in the ratio 3:5:7 if the rope is 33 feet 9 inches, fi

Olin [163]

P-81
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r-189
find out how many inches the rope is then divide by 15 total parts then multiply each ratio by that

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3 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

6 months ago

How do you find the area of a cone?

Gala2k [10]

To find of a cone

$\pi \: r \sqrt{r}^{2} + h {}^{2}$
hope this help you
may i got a brainliest please

8 0

2 years ago

Pls pls pls pls pls help

raketka [301]

Answer:38x-34

Step-by-step explanation:

f(x)=x^2+3x-7

g(x)=5x-3

We multiply the entire F equation times two, (x^2+3x-7)*4=

(4x^2+12x-28)

Now the entire g equation by 2, (5x-3)*2

(10x-6)

Now we add both equation

(4x^2+12x-28)+(10x-6)

(4x^2+22x-34)

(4x*4x+22x-34)

(16x+22x-34)

38x-34

Hopefully this is correct :)))

7 0

2 years ago

Mary has a rectangular garden that she needs to buy soil for. The length of the garden can be represented by 5x-1, and the width

Lera25 [3.4K]

Answer:

A = (5x - 1) (x^2 + 4)

Step-by-step explanation:

Area = length × width

= (5x - 1) (x^2 + 4)

7 0

2 years ago