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skelet666 [1.2K]
4 years ago
11

Which of the following statements accurately compares f(x) and g(x)? Choose all that apply.

Mathematics
2 answers:
larisa86 [58]4 years ago
8 0

The growth factor of function g is 56/40 = 1.4. This number is larger than the 1.3 growth factor in f(x). The statements that apply are ...

... A. The initial values of f(x) and g(x) are the same.

... C. The growth factor of f(x) is less than the growth factor of g(x).

Anon25 [30]4 years ago
8 0

Answer: a and c

Step-by-step explanation:

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Aiden bought some noteboks and book covers for the upcoming school year.He bought a total of 13 items.Each notebook costs $1.37,
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1.37x + 1.08y = 16.36
x + y = 13

x = 13 - y
1.37* (13-y) + 1.08y = 16.36
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3 years ago
Which of the following arithmetic sequences have a common difference of ? -4,-1.5,1,3.5,6,8.5 1.5,3,4.5,6,7.5
zavuch27 [327]
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Gary used candle molds, as shown, to make candles that were perfect cylinders and spheres:What is the approximate difference in
Nikolay [14]
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6 0
3 years ago
The population of a town 4 years ago was 50,000
tino4ka555 [31]

Answer:

population will be 79806.

Step-by-step explanation:

Population of a town 4 years ago  was 50,000

Population of town had grown exponentially and present population is 63,124.

So the formula of the population growth will be

A_{n}=A_{o}(r)^{n-1}

Where A_{n} = Final population n = number of years.

           A_{o} = Initial population

           r = rate of increase in population per year.

so  63124 = 50,000 (r)^{4-1}

r^{3}=\frac{63124}{50000}= 1.26428

r=(1.26428)^{\frac{1}{3} }

= 1.0813

Now we have to find the population after 4 years from now.

A_{n} =  63124(1.08)^{4-1}

       =  63124(1.08)^{3}

       = 63124 × 1.264

       = 79806

Therefore, after 4 years from now population will be 79806.

8 0
4 years ago
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