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3 years ago

Combine like terms. What is a simpler form of the expression? -3(-4y+3)+7y

Mathematics

1 answer:

kupik [55]3 years ago

8 0

Answer:

19y - 9

Step-by-step explanation:

-3(-4y + 3) + 7y =

Distribute the -3.

= 12y - 9 + 7y

Combine like terms: 12y + 7y

= 19y - 9

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Which step comes last when using the divide-center method to find the trend line on a scatterplot?

stepan [7]

Answer:

Connect the two centers to produce the trend line

Step-by-step explanation:

When the dots have been plotted, there are three steps to find the trend line on a scatter plot:

1. Draw a vertical line that separates the full set of points into two sets, each with the same number of dots.

2.Mark with a special sign (e.g + or ×) the middle value in each of the two sets obtained in the previous step.

3.Join the two marks mentioned in the step (2) with a straight line, and extend it to the edges of the graph. This line is the trend line, and this is the last step.

Thus, the last step when using the divide-center method to find the line on scatter plot is Connect the two centers to produce the trend line.

6 0

3 years ago

Read 2 more answers

Find the length of arc AB for each circle.

Eddi Din [679]

Answer:

see explanation

Step-by-step explanation:

The length of the arc is calculated as

AB = circumference of circle × fraction of circle

(11)

AB = 2πr × $\frac{90}{360}$

= 2π × 7 × $\frac{9}{36}$

= 14π × $\frac{1}{4}$

= $\frac{7}{2}$ π in

(12)

AB = 2πr × $\frac{135}{360}$ ( r = 20 ÷ 2 = 10 )

= 2π × 10 × $\frac{3}{8}$

= 20π × $\frac{3}{8}$

= $\frac{60}{8}$ π

= $\frac{15}{2}$ π cm

8 0

3 years ago

Solve for x and y by substitution method

zubka84 [21]

Answer:

Step-by-step explanation:

Because if you simplify you get that

3 0

3 years ago

Read 2 more answers

Find the cdf F(x) associated with each of the following probability density functions. Sketch the graphs of f(x) and F(x).

wolverine [178]

Answer:

See steps below

Step-by-step explanation:

$\bf f(x)=3(1-x)^2\;(0$

$\bf F(x)=\int_{0}^{x}f(t)dt=\int_{0}^{x}3(1-t)^2dt=3\int_{0}^{x}(1-t)^2=1-(1-x)^3$

The cdf associated with f is

$\bf \boxed{F(x)=1-(1-x)^3}$ for 0<x<1

<h3>See picture 1 </h3>

The median is a point x such that

F(x) = ½

so, the median is

$\bf 1-(1-x)^3=1/2\rightarrow (1-x)^3=1/2\rightarrow \boxed{x=1-\sqrt[3]{2}}$

The 25th percentile equals the 1st quartile and is a point x such

F(x) = ¼

and the 25th percentile is

$\bf 1-(1-x)^3=1/4\rightarrow (1-x)^3=3/4\rightarrow \boxed{x=1-\sqrt[3]{3/4}}$

$\bf f(x)=\frac{1}{x^2}\;(1$

$\bf F(x)=\int_{1}^{x}f(t)dt=\int_{1}^{x}\frac{dt}{t^2}=1-\frac{1}{x}$

The cdf associated with f is

$\bf \boxed{F(x)=1-\frac{1}{x}}$ for x>1

<h3>See picture 2 </h3>

The median is

$\bf 1-\frac{1}{x}=\frac{1}{2}\rightarrow \boxed{x=2}$

The 25th percentile is

$\bf 1-\frac{1}{x}=\frac{1}{4}\rightarrow \boxed{x=4/3}$

f(x) = 1/3 for 0<x<1 or 2<x<4

$\bf F(x)=\int_{0}^{x}\frac{dt}{3}=\frac{x}{3}\;(0$

$\bf F(x)=\frac{1}{3}+\int_{2}^{x}\frac{dt}{3}=\frac{1}{3}+\frac{x-2}{3}=\frac{x-1}{3}\;(2$

The cdf associated with f is

$\bf F(x)=\frac{x}{3}$ for 0<x<1

$\bf F(x)=\frac{x-1}{3}$ for 2<x<4

<h3>See picture 3 </h3>

The median is

$\bf \frac{x-1}{3}=1/2\rightarrow x=1+3/2\rightarrow \boxed{x=5/2}$

The 25th percentile is

$\bf \frac{x}{3}=1/4\rightarrow \boxed{x=3/4}$

4 0

4 years ago

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ella [17]

20 days until they work together again

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3 years ago