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zavuch27 [327]
3 years ago
14

Combine like terms. What is a simpler form of the expression? -3(-4y+3)+7y

Mathematics
1 answer:
kupik [55]3 years ago
8 0

Answer:

19y - 9

Step-by-step explanation:

-3(-4y + 3) + 7y =

Distribute the -3.

= 12y - 9 + 7y

Combine like terms: 12y + 7y

= 19y - 9

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The snack shop makes 3 mixes of nuts in the following proportions.
Julli [10]

Answer:

A=\begin{bmatrix}6 & 5 & 3\\ 2 & 3 & 4\\ 2 & 2 & 3\end{bmatrix}

B=\begin{bmatrix}25\\ 18\\ 35\end{bmatrix}

Step-by-step explanation:

It is given that the snack shop makes 3 mixes of nuts in the following proportions.

Mix I: 6 lbs peanuts, 2 lbs cashews, 2 lbs pecans.

Mix II: 5 lbs peanuts, 3 lbs cashews, 2 lbs pecans.

Mix III: 3 lbs peanuts, 4 lbs cashews, 3 lbs pecans.

they received an order for 25 of mix I, 18 of mix II, and 35 of mix III.

We need to find the matrices A & B for which AB gives the total number of lbs of each nut required to fill the order.

                      Mix I             Mix II              Mix III

peanuts             6                  5                    3

cashews            2                  3                    4

pecans              2                   2                    2

A=\begin{bmatrix}6 & 5 & 3\\ 2 & 3 & 4\\ 2 & 2 & 3\end{bmatrix}

B=\begin{bmatrix}25\\ 18\\ 35\end{bmatrix}

The product of both matrices is

AB=\begin{bmatrix}6 & 5 & 3\\ 2 & 3 & 4\\ 2 & 2 & 3\end{bmatrix}\begin{bmatrix}25\\ 18\\ 35\end{bmatrix}

AB=\begin{bmatrix}6\cdot \:25+5\cdot \:18+3\cdot \:35\\ 2\cdot \:25+3\cdot \:18+4\cdot \:35\\ 2\cdot \:25+2\cdot \:18+3\cdot \:35\end{bmatrix}

AB=\begin{bmatrix}345\\ 244\\ 191\end{bmatrix}

Therefore matrix AB gives the total number of lbs of each nut required to fill the order.

8 0
3 years ago
What is the 200 hundredth digit in 5/6
sladkih [1.3K]

5/6 = .83333333(repeating)

the 200th digit is 3

3 0
3 years ago
What is the absolute value equation for this graph?
tatyana61 [14]

Answer:

y = -|x +2| +4

Step-by-step explanation:

The parent function y=|x| is shifted to the left 2 units, so x is replaced by x+2. It is reflected across the x-axis, so is multiplied by -1: -|x+2|. It is shifted up 4 units, so has 4 added to it:

y = -|x+2| + 4

3 0
3 years ago
In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En
mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

\frac{dy}{dx} = 3t^{2} - 2t - 27

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

3t^{2} - 2t - 27 = 0

So

a = 3, b = -2, c = -27

Then

\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328

So

t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35

t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55

y = t^{2} - 4 = (3.35)^2 - 4 = 7.22

The first point is (27.55, 7.22)

t = -2.685

x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3

y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21

The second point is (-11.3, 3.21).

8 0
3 years ago
the amount of gasoline used by a car varies jointly as the distance travelled and the square root of the speed.Suppose a car use
klemol [59]

Answer:

200 litres

Step-by-step explanation:

let g be gasoline used, d the distance travelled and s the speed, then the equation relating the quantities is

g = kd\sqrt{s} ← k is the constant of variation

To find k use g = 25, d = 100 and s = 100, then

25 = k × 100 × \sqrt{100} = k × 100 × 10 = 1000k ( divide both sides by 1000 )

0.025 = k

g = 0.025d\sqrt{s} ← equation of variation

When d = 1000 and s = 64, then

g = 0.025 × 1000 × \sqrt{64} = 0.025 × 1000 × 8 = 200

4 0
3 years ago
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