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3 years ago

Simplify the following expression 4w x 3w x 2y x 2y

Mathematics

2 answers:

Julli [10]3 years ago

8 0

Answer:

48w^2x^3y^2

Step-by-step explanation: Is all i found hope i helped sorry if i didn't

Anestetic [448]3 years ago

4 0

Answer:

48w^2y^2

I used a simplify calculator I hope this is correct.

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A survey of 398 children given at a local elementary school showed that 175 like chocolate ice cream, 225 like pistachio ice cre

Maru [420]

225-175=50
175-50=125
125 chidren liked both chocolate and pistachio ice cream.
Check: 398-123=275
275-125=150
225-125=100
175-125=50
100+50=150
150-150=0

3 0

3 years ago

Mr. Peate is building a rectangular fence around his house. The fence will be 32 feet long and 29 feet wide. What will be the pe

kupik [55]

Answer:

112

Step-by-step explanation:

32*2+29*2=112

8 0

3 years ago

The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago

A kite flying in the air has an 11 - ft line attached to it. Its line is pulled taut and casts an 8 - ft shadow. Find the height

Fofino [41]

The line, shadow and the height form a right angled triangle so we can apply the Pythagoras theorem here:-

11^2 = h^2 + 8^2 where h = height of the kite
h^2 = 11^2 - 8^2
h^2 = 57
h = 7.55 ft to the nearest foot Answer

5 0

3 years ago

Read 2 more answers

Mikey has two mice that were about the same age and weight Mikey fed each of the 2 mice a different feed for a month. He measure

Nadusha1986 [10]

The following is the rest of the question:
------------------------------------------------------
Mikey's results showed that although both mice gained weight over the month, mouse 2 gained more weight than mouse 1.Which graph below best shows these results?
The complete figure is attached
=========================================================
Solution:
---------------
Graph (1)⇒⇒⇒ mouse 2 has constant weight and mouse 1 gained weight

Graph (3)⇒⇒⇒ mouse 2 has did not gain weight and mouse 1 gained weight

∴ Graph (1) and (3) are incorrect because both mice gained weight .

Graph (4) is incorrect because mouse 2 gained more weight than mouse 1

So, the correct answer is graph (2)

5 0

3 years ago

Read 2 more answers