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3 years ago

If the measure of angle BDC=100°, measure of angle A = 50°, and measure of angle DBC= 30°. which statement is true?

Mathematics

1 answer:

expeople1 [14]3 years ago

7 0

B. triangle ABC is isosceles. The angles add up 180 degrees.

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What's 486.12 fraction

melisa1 [442]

486.12 as fraction is 12153/25
HOPE THIS HELPS

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3 years ago

Solve each of the following equations for xx using the same technique as was used in the Opening Exercise.

Brrunno [24]

Answer:

The value of the x is 1/9.

Step-by-step explanation:

Data provided in the question is:

$3^2/x=81$

To find out:-

the value of x.

Solution for the equation:-

$3^2/x = 81\\9/x=81\\9/81=x\\1/9=x\\$

On solving the given question or equation by using mathematics of algebra we find out the value of x to be 1/9.

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3 years ago

What the hypothenuse of a right with length of 6 and 8

Aloiza [94]

This is a pythagorean triple --> 3-4-5
Although you notice it is doubled but with the same pattern --> 6-8-10

Thus, the hypotenuse is 10.

8 0

3 years ago

Read 2 more answers

If Ben invests $4500 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that

pogonyaev

$Step \; 1: \; Assing \; variable \; for \; the \; unknown \; that \; we \; need \; to \; find.\\Let \; x \; be \; additional \; money \; invested$

$Step \; 2: \; Use \; the \; appropriate \; formula \; of \; simple \; interest \; set \; up \; an \; equation\\Interest \; earned \; each \; year = \; Amount \; invested \times annual \; rate \; of \; interest\\\\Amount \; invested \; in \; 4 \% \; rate \; of \; interest=\$4500\\Amount \; invested \; in \; 5\frac{1}{2}\% \; rate \; of \; interest= \$x\\Amount \; invested \; totally \; in \; 4\frac{1}{2}\% \; rate \; of \; interest = \$(4500+x)$

$Interest \; earned \; in \; 4\% \; interest \; rate\\ = \; 4500(4\%)=180\\Interest \; earned \; in \; 5\frac{1}{2}\% \; interest \; rate\\ = x(5\frac{1}{2}\%)=0.055x\\Interest \; earned \; totally \; in \; 4\frac{1}{2}\% \; interest \; rate = (4500+x)(4\frac{1}{2}\%)\\=0.045(4500+x)$

$\\\\So, \; the \; equation \; would \; be:\\180+0.055x=0.045(4500+x)$

$Step \; 1: \; Distribute \; 0.045 \; in \; the \; right \; side\\180+0.055x=202.5+0.045x\\\\Step \; 2: \; Subtract \; 0.045x \; and \; 180 \; on \; both \; sides \; to \; get \; x \; alone\\0.055x-0.045x=202.5-180\\\\Step \; 3: \; Combine \; Like \; Terms\\0.01x=22.5\\\\Step \; 4: Divide \; 0.01 \; on \; both \; sides\\\frac{0.01x}{0.01}=\frac{22.5}{0.01}\\\\Step \; 5: \; Simplifying \; fraction \; on \; both \; sides\\x=2250$

$\underline{Conclusion:}\\Ben \; should \; invest \; additional \; money \; of \; \$2250$

5 0

3 years ago

Solve by substitution or elimination 5x+3y=-15 -8x-2y=10

Cerrena [4.2K]

Answer:

x=0, y=-5

Step-by-step explanation:

The system is

(1) 5x+3y=-15

(2) -8x-2y=10

Let's solve it by elimination. In order to do it, you have to multiply the equations by suitable numbers in such a way that when you add the 2 equations, one of the unknowns is eliminated

Multiply (1) by 2 and (2) by 3

(1) 10x+6y=-30

(2) -24x-6y=30

Add the two equations

10x-24x+6y-6y=-30+30 ----> -14x=0---->x=0

Now replace this value in any equation, for example in (1)

6y=-30 ----> y=-30/6----> y=-5

5 0

3 years ago

Read 2 more answers