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3 years ago

11

A sum of money when invested for a definite period at r% simple interest will yield an interest of rm80 .using the same interest

rate, find the interest earned if the sum is tripled and the investment period is doubled

1 answer:

maks197457 [2]3 years ago

7 0

The invest could probably be maybe 8% for a question

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kvv77 [185]

Answer:

Girls in Mr. Chang's class: 28 - 21 ; # girl students = # total students - # boy students ; 7 girl students.

Boys in Mr. Chang's class: 28 - 7 ; # boy students = # total students - girl students ; 21 boy students.

8 0

3 years ago

What two rational expressions sum to 3x+4/x^2-6x+5?

Lubov Fominskaja [6]

Answer:

$\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}$

Step-by-step explanation:

The given rational expression is:

$\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}$

We can use concept of Partial Fractions to solve this problem. Let,

$\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}$

Multiplying both sides by (x - 1)(x - 5), we get:

$3x+4=A(x-5)+B(x-1)$

Substituting x = 5, we get:

$3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}$

Substituting x = 1, we get:

$3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}$

Substituting the value of A and B, back in the original equation, we get:

$\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}$

4 0

3 years ago

Dominic spent 2 3/4 hours on art project. Rachel worked 1 1/3 times as long. How many hours did Rachel work for?

N76 [4]

3 and 2/3 hours.

Multiply the number of hours Dominic spent by the scale factor.

3 0

4 years ago

Read 2 more answers

What is the distance from the origin to point A graphed on the complex plane below?

Degger [83]

Answer: False

Step-by-step explanation:

You didn't give the coordinate plane that I was supposed to use while helping you.

3 0

3 years ago

How does the value of log Subscript 2 Baseline 100 compare with the value of Log Subscript 6 Baseline 20?.

attashe74 [19]

You can use the change of base formula to get

$\log_2(100) = \frac{\log(100)}{\log(2)} \approx 6.643856$

and also

$\log_6(20) = \frac{\log(20)}{\log(6)} \approx 1.671950$

In general, the change of base formula is

$\log_b(x) = \frac{\log(x)}{\log(b)}$

8 0

2 years ago