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Slav-nsk [51]
3 years ago
9

Aaron, Blaine, and Cruz are solving the equation

Mathematics
2 answers:
stiv31 [10]3 years ago
7 0

Answer:

All three chose a valid first step toward solving the equation.

All approaches are algebraically correct

wolverine [178]3 years ago
4 0

Answer:

the answer is D

Step-by-step explanation:

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-2 (t+2) +5 t = 6 t + 11
vovikov84 [41]

Answer:

The answer is T=-5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Pls look at the picture and answer
melisa1 [442]

Answer:

-0.5 goes between -2 and 1

0.5 goes between -2 and 1

-4.5 goes below -2

-2.5 goes below -2

1.5 goes above 1

4 goes above 1

5 0
2 years ago
Read 2 more answers
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
2 years ago
What are perfect numbers between 1 and 28
snow_lady [41]

Answer:

i was trying to help u but ok delete my answer

Step-by-step explanation:

5 0
3 years ago
In January, the normal low temperature in New Haven, Connecticut is 17°F while the normal high is 35°F. What is the spread betwe
kiruha [24]
I think it is 23 degreese 
7 0
3 years ago
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