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3 years ago

What is the equation in a point-slope form of the line that passes through the point (-8, 5) and has a slope of 12?

Mathematics

1 answer:

Anton [14]3 years ago

4 0

Answer:

y-5=12(x+8)

Step-by-step explanation:

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Whats the slope of the 2 points (6,-6) & (-1,-3)

Bingel [31]

$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{(-6)}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{6}}}\implies \cfrac{-3+6}{-7}\implies -\cfrac{3}{7}$

6 0

3 years ago

45x=180;x=4 a. yes b. no,x=6 c. no,x=2

sveta [45]

I hope this helps you

5 0

3 years ago

Jessica deposited $2000 into an account with a 7.6% annual interest rate, compared quarterly. Assuming that no withdrawals are m

joja [24]

Answer:

Step-by-step explanation:

use

i=prt

i=interest

p= principal value

r=rate

t=time

now you want to find time then it will be

t= i/pr

put values

t= 3722/(2000*7.6%)

t= 2 years

calculation is in fraction but your question given you annual interest so time will also be 2 years not in months

8 0

3 years ago

Read 2 more answers

the probability of winning the shell games if you randomly pick is 1 in 3. what would be the appoximate probability of winning 4

Olenka [21]

Answer:

1/81

Step-by-step explanation:

7 0

3 years ago

Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a

NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

$P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

And then substitute the values in it then

$Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

Learn more about probability here

brainly.com/question/24756209

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7 0

1 year ago