Isosceles trapezoid
<ONM = <LON = 100
<OLM = <NML = 1/2(360 - 2(100))
= 1/2(360 - 200)
= 1/2(160)
= 80
Answer
<OLM = 80 degress
Answer:
Step-by-step explanation:
As per Janayda,
From the figure attached,
In ΔTRQ,
m∠TRQ + m∠RQT + m∠QTR = 180°
25° + m∠RQT + 35° = 180°
m∠RQT = 180° - 60°
m∠RQT = 120°
Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]
m∠PQT = 180° - m∠RQT
= 180° - 120°
= 60°
In right angled triangle TPQ,
m∠TPQ + m∠PQT + m∠PTQ = 180°
90° + 60° + m∠PTQ = 180°
m∠PTQ = 180° - 150°
= 30°
Similarly, other angles can also be evaluated from the given information.
In ΔQTP and ΔNTP,
TP ≅ TP [Reflexive property]
NP ≅ PQ [Given]
ΔQTP ≅ ΔNTP [By LL postulate for congruence]
Therefore, Janayda is correct.
While Sirr is incorrect.
Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.
Answer:
7x2 + 14x = 0
x2 + 3x -5 = 0
x2 - x = 3x + 7
Step-by-step explanation:
A quadratic equation has the highest power of x to the second power. It must have x to the second power
7x2 + 14x = 0 quadratic
x3 - 3x2 + 1 = 0 not quadratic but cubic
5x - 7 = 0 not quadratic but linear
x2 + 3x -5 = 0 quadratic
x - 5 = 9x + 7 not quadratic but linear
x2 - x = 3x + 7 quadratic
Answer:
There are 69120 total combinations.
Step-by-step explanation:
To find the total number of combinations, we multiply all these values. So
16 people
18 colors
12 shades
20 tertiary gradients.
How many combinations are there total?
16*18*12*20 = 69120
There are 69120 total combinations.
