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Harman [31]
3 years ago
10

An artist makes a scale drawing of a new lion enclosure at the zoo. The scale is 1 in : 25 ft. On the drawing, the length of the

enclosure is 7.25 inches. What is the actual length of the lion enclosure in feet?
Mathematics
1 answer:
8090 [49]3 years ago
4 0

Answer:

The actual length of the lion enclosure is <u>181.25 feet</u>.

Step-by-step explanation:

Given:

An artist makes a scale drawing of a new lion enclosure at the zoo.

The scale is 1 in : 25 ft.

On the drawing, the length of the enclosure is 7.25 inches.

Now, to find the actual length of the lion enclosure in feet.

Let the actual length of the lion enclosure in feet be x.

<em>As given the  scale is 1 in : 25 ft.</em>

<em>So, 1 in is equivalent to 25 ft.</em>

<em>Thus, 7.25 inches is equivalent to </em>x.<em />

Now, to get the actual length of the lion enclosure by using cross multiplication method:

\frac{1}{25} =\frac{7.25}{x}

<em>By cross multiplying we get:</em>

x=181.25\ feet.

Therefore, the actual length of the lion enclosure is 181.25 feet.

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If you were to add 12.52, 349.0 and 8.24, how many significant digits should the answer have? a.. three. c.. five. b.. four. d..
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3 years ago
The total cost of a color printer is $186.16 including tax. If the tax rate is 7%, what is the original cost of the color printe
Galina-37 [17]

Answer:

<u>The original cost of the printer before adding the tax was $ 173.98</u>

Step-by-step explanation:

Total cost of the color printer, including tax = $ 186.16

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Original cost of the printer, before tax = x

For answering the question, let's use the Rule of Three Simple, this way:

Percentage        Value

107%                  186.16

100%                     x

x * 107 = 186.16 * 100

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x = 18,616/107

x = 173.98

<u>The original cost of the printer before adding the tax was $ 173.98</u>

6 0
3 years ago
What is the probability that a five-card poker hand contains a flush, that is, five cards of the same suit?
Liono4ka [1.6K]

\displaystyle |\Omega|=\binom{52}{5}=\dfrac{52!}{5!47!}=\dfrac{48\cdot49\cdot50\cdot51\cdot52}{2\cdot3\cdot4\cdot5}=2598960\\ |A|=\binom{13}{5}\cdot4=\dfrac{13!}{5!8!}\cdot4=\dfrac{9\cdot10\cdot11\cdot12\cdot13}{2\cdot3\cdot4\cdot5}\cdot4=5148\\\\ P(A)=\dfrac{5148}{2598960}=\dfrac{33}{16660}\approx0.2\%

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Please help me....trying to get my HS diploma, i did not graduate :(
jolli1 [7]

Answer:

A.

Step-by-step explanation:

so, the equation is

h(t) = -t² + 7t

so, we need to find the solutions for t (the time when the ball is exactly 10 ft in the air). there had to be 2 solutions, as the ball first goes up passing the 10 ft height, and then comes back down again, passing the 10 ft mark a second time. and between these 2 times the ball is higher (but not equal, so, we can only use < or > as inequality signs) than 10 ft.

10 = -t² + 7t

-t² + 7t - 10 = 0

the generation solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = t

a = -1

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t = (-7 ± sqrt(7² - 4×-1×-10))/(2×-1) =

= (-7 ± sqrt(49 - 40))/-2 = (-7 ± sqrt(9))/-2

t1 = (-7 + 3)/-2 = -4/-2 = 2 seconds

t2 = (-7 - 3)/-2 = -10/-2 = 5 seconds

so, between 2 and 5 seconds airtime the ball is higher than 10 ft.

and remember : HIGHER THAN.

so, we cannot use any equality (like <= or >=).

t must be higher than 2 and lower than 5 :

2 < t < 5

3 0
2 years ago
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