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klemol [59]
3 years ago
14

Is (6, –2) a solution to this system of equations? y = –1/6 x − 1 y = 1/6 x − 3

Mathematics
1 answer:
Liula [17]3 years ago
5 0

Answer:

Yes, (6, -2) is a solution to the given system of equations.

Step-by-step explanation:

Please write  y = –1/6 x − 1 y = 1/6 x − 3 as follows, for greater clarity:

y = (–1/6)x − 1

y = (1/6)x − 3

Let's actually solve this system:

y = (–1/6)x − 1

y = (1/6)x − 3

-----------------------

2y = -4, or y = -2

Now find x.  Arbitrarily we choose to use the first equation for this purpose:

y = (-1/6)x - 1.  We set y = -2 and find x:    -2 = (-1/6)x - 1

Combining the constants, we get -1 = (-1/6)x, or 6 = x

Yes, (6, -2) is a solution to the given system of equations.

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A shoe store donated a percent of every sale to charity. a the total sales were $9,800 so the store donated $588. What percent o
Gnom [1K]

Answer:

They donated 6%.

Step-by-step explanation:

The total sales were $9800.

The amount donated is $588.

We want to know what percent of 9800 is 588.

Let's make an equation.

what percent of 9800 is 588

x/100 • 9800 = 588

Divide by 9800.

x/100 = 0.06

Multiply by 100.

x = 6

They donated 6%.

Hope this helps!

3 0
2 years ago
What are two factors of the composite number 46 other than 1 and 46? A. 3 and 7 B. 2 and 13 C. 2 and 23 D. 3 and 33
riadik2000 [5.3K]

Answer:

2 and 23 are the factors of the composite number 46 .

Option (C) is correct.

Step-by-step explanation:

As given in the question  46 is a composite number .

Definition of factors

"Factors" are the numbers you multiply to get another number.

As 46 is written as

46 = 2 × 23

Therefore the factors of the composite numbers 46 are 2 and 23 .


6 0
3 years ago
Read 2 more answers
The two roots a+sqrb and a-sqr b are called _______radicals.
astraxan [27]

Answer:

Conjugate radicals.

Step-by-step explanation:

The two roots a+sqrb and a-sqr b are called conjugate radicals.

6 0
2 years ago
Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).
lions [1.4K]

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}

(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill

\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}

6 0
1 year ago
The base of a cylinder has a radius of 5 cm. What is its area?
Oksi-84 [34.3K]

Answer:

157

Step-by-step explanation:

formula- 2 x 3.14 x 5 squared

6.28 x 5 squared

6.28 x 25

157

4 0
3 years ago
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