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klemol [59]
3 years ago
14

Is (6, –2) a solution to this system of equations? y = –1/6 x − 1 y = 1/6 x − 3

Mathematics
1 answer:
Liula [17]3 years ago
5 0

Answer:

Yes, (6, -2) is a solution to the given system of equations.

Step-by-step explanation:

Please write  y = –1/6 x − 1 y = 1/6 x − 3 as follows, for greater clarity:

y = (–1/6)x − 1

y = (1/6)x − 3

Let's actually solve this system:

y = (–1/6)x − 1

y = (1/6)x − 3

-----------------------

2y = -4, or y = -2

Now find x.  Arbitrarily we choose to use the first equation for this purpose:

y = (-1/6)x - 1.  We set y = -2 and find x:    -2 = (-1/6)x - 1

Combining the constants, we get -1 = (-1/6)x, or 6 = x

Yes, (6, -2) is a solution to the given system of equations.

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<h2>The product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}</h2>

Step-by-step explanation:

We have,

\dfrac{7x}{x-4}.\dfrac{x}{x+7}

To find, the product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = ?

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= \dfrac{7x.x}{(x-4)(x+7)}

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