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g100num [7]
4 years ago
11

Are 3x and 4y like terms

Mathematics
2 answers:
klasskru [66]4 years ago
8 0

Answer:No

Step-by-step explanation: 3x and 4y have different variables.

aliina [53]4 years ago
4 0

Answer:

NO it isnt!

Step-by-step explanation:

3x is related to terms with x! And 4y is related to terms with y!

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1/4 foot every 3/4 hour how many feet in one hour
RUDIKE [14]

For this case we propose a rule of three:

\frac {1} {4} foot -------------> \frac {3} {4} hour

x -----------------------------------> 1 hour

Where "x" represents the amount of foot in one hour.

x = \frac {1 * \frac {1} {4}} {\frac {3} {4}}\\x = \frac {\frac {1} {4}} {\frac {3} {4}}\\x = \frac {4 * 1} {3 * 4}\\x = \frac {4} {12}\\x = \frac {1} {3}

So, we have\frac {1} {3} foot every hour.

Answer:

\frac {1} {3}foot every hour

4 0
4 years ago
Write and solve an equation for the scenario. Angela rented a car for $29.99 a day plus a one time insurance fee of $5. Her bill
Gnesinka [82]

Answer:

29.99x +5 =124.96 ; x = 4

Step-by-step explanation:

X is how many days. She rented the car for 4 days.

3 0
3 years ago
Read 2 more answers
Meg conducted a survey of four school cafeterias to find the number of students who like sandwiches for lunch. The results of he
Natasha_Volkova [10]
C. 38.46%       To get your answer you divide the number of students who liked sandwiches by total number of students in the cafeteria.   Example:  10/26=.3846 which is 38.46%
6 0
3 years ago
Read 2 more answers
What is 10^8 written in standard form?
Paladinen [302]

Answer:

100,000,000 = 10^8

Step-by-step explanation:

3 0
3 years ago
I need to verify identity functions for a one to one function.
Eddi Din [679]

We have the function

f(x)=(x+6)^3

1. For f^-1:

Let y = f(x) = (x+6)^3

Switch x and y to get:

x=(y+6)^3

And solve for y

\begin{gathered} x^{\frac{1}{3}}=y+6 \\ x^{\frac{1}{3}}-6=y+6-6 \\ x^{\frac{1}{3}}-6=y \end{gathered}

And we have y = f^-1(x)

Answer blank 1:

f^{-1}(x)=x^{\frac{1}{3}}-6

2. For f o f^-1 (x):

(f\circ f^{-1})(x)=f(f^{-1}(x))

And solve

\begin{gathered} =f(x^{\frac{1}{3}}-6) \\ =(x^{\frac{1}{3}}-6+6)^3 \\ =(x^{\frac{1}{3}})^3 \\ =x \end{gathered}

answer blank 2

x^{\frac{1}{3}}-6

answer blank 3

x^{\frac{1}{3}}-6

answer blank 4

x^{\frac{1}{3}}

3. For f^-1 o f:

(f^{-1}\circ f)(x)=f^{-1}(f(x))

Solve

\begin{gathered} =f^{-1}((x+6)^3) \\ =\sqrt[3]{(x+6)^3}-6 \\ =x+6-6 \\ =x \end{gathered}

answer blank 5

(x+6)^3

answer blank 6

(x+6)^3

answer blank 7

x+6

4 0
1 year ago
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