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12345 [234]
3 years ago
12

A metal alloy bolt is initially at 100.0°C. It is dropped into a coffee cup calorimeter containing 50.0 g of water at a temperat

ure of 20.0°C. After stirring, the final temperature of both bolt and water is 25.0°C. Assuming no heat losses, and that the specific heat (capacity) of water is 4.18 J/(g ∙ K), what is the heat capacity of the bolt in J/K?
Business
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

the heat capacity of the bolt is 13.9 J/K

Explanation:

J/K is short of " joule per kelvin", is the international system unit of heat capacity

heat energy = (mass of substance)(specific heat)(change in temperature)

Q = mc∆T

Q = heat energy (Joules, J)

m = mass of a substance (kg)

c = specific heat (units J/kg∙K)

∆ is a symbol meaning "the change in"

∆T = change in temperature (Kelvins, K)

Heat gained by water = heat lost by copper  = Q = mC∆T = (50 g)(4.18 J/g/deg)(5 deg) = 1045 J   = C x ∆T

C = 1045 J/75 = 13.9 J/deg

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Hushovd Iron Works has collected the following data for its Thunderbolt line of​ products: Direct materials standard 15 pounds p
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Answer:

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The direct materials quantity variance represents a difference between what was actually produced and the standard or idea that should have been produced especially with regards to the use of direct materials.

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Kindly note that the multiple options in the question above are for a different set of figures and a different question.

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