Since opposite angles and sides are equal, then the quadrilateral ABCD is a parallelogram.
Given that, ABCD is a quadrilateral, segment AB is congruent to segment CD, ∠1 is congruent to ∠2.
We need to prove that ABCD is a parallelogram.
<h3>
How to prove a given quadrilateral is a parallelogram?</h3>
If one pair of opposite sides of a quadrilateral are both parallel and congruent, then it’s a parallelogram.
From the given quadrilateral ABCD:
AB=CD (Given)
∠1=∠2 (Given)
AC=AC (Diagonal)
From ASA congruency ΔABC and ΔADC are congruent.
By CPCT, AD=BC and ∠ABC=∠ADC.
Since opposite angles and sides are equal, then the quadrilateral ABCD is a parallelogram.
To learn more about parallelogram visit:
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The value of sine of angle Q is 1.16
<u>Explanation:</u>
Given:
ΔQRS is a right angle triangle
∠S = 90°
QS = 33
SR = 56
QR = 65
Sin(∠Q) = ?
We know:
![sin \alpha = \frac{perpendicular}{hypotenuse}](https://tex.z-dn.net/?f=sin%20%5Calpha%20%20%3D%20%5Cfrac%7Bperpendicular%7D%7Bhypotenuse%7D)
So,
![sin(Q) = \frac{QR}{RS} \\\\Sin (Q) = \frac{65}{56} \\\\sin (Q) = 1.16](https://tex.z-dn.net/?f=sin%28Q%29%20%3D%20%5Cfrac%7BQR%7D%7BRS%7D%20%5C%5C%5C%5CSin%20%28Q%29%20%20%3D%20%5Cfrac%7B65%7D%7B56%7D%20%5C%5C%5C%5Csin%20%28Q%29%20%3D%201.16)
Therefore, the value of sine of angle Q is 1.16
Answer:
-100
Step-by-step explanation:
4(-25)=-100
First, find the area of footbakk field in square yards:
sq. yd.
Next, if 1 yd = 91.44 cm, then 1 sq. yd=91.44·91.44 sq. cm=8,361.2736 sq. cm.
At last, you have that
1 sq. yd - 8,361.2736 sq. cm.
6000 sq. yd - x sq. cm.
Mathematically,
sq. cm.
Note that 1 m=100 cm and 1 sq. m=10000 sq. cm, then
50167641.6 sq. cm=5016.76416 sq. m
Answer: 5016.76416 sq. m
A shape with 4 sides is a quadralateral