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vodka [1.7K]
3 years ago
11

At the park, there is a triangular sandbox with base = 12ft and height = 4ft. A drawing of the sandbox is shown above. Brie want

s to make another, similar sandbox at home with base=8ft.
Mathematics
1 answer:
sammy [17]3 years ago
3 0

Your question is not clear, but it looks as though you want to know how Brie can make a similar sandbox with base = 8ft.

Answer:

For Brie to make a similar sandbox, he must use a base = 8ft, and height = (8/3)ft

Step-by-step explanation:

It is possible for Brie to make a similar triangular sandbox with base = 12ft and height = 4ft.

All he must ensure is that the ratio of base to height of the original sandbox is the same ratio of base to height of the one he is trying to make.

The original sandbox is 12:4

Because he wants to use a base = 8ft, the sandbox he is trying to make is 8:x

Where x is the height of the sandbox he is trying to make.

Then for these sandboxes to be similar, the ratio 12:4 = 8:x

=> 12/4 = 8/x

12x = 8 × 4

12x = 32

x = 8/3

The height must be (8/3)ft

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Masteriza [31]

Answer:

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 15.4 inches, and standard deviation of 3.5 inches.

This means that \mu = 15.4, \sigma = 3.5

16 items are chosen at random

This means that n = 16, s = \frac{3.5}{\sqrt{16}} = 0.875

What is the probability that their mean length is less than 16.8 inches?

This is the p-value of Z when X = 16.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16.8 - 15.4}{0.875}

Z = 1.6

Z = 1.6 has a p-value of 0.9452.

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

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