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ahrayia [7]
2 years ago
10

Watch help video

Mathematics
1 answer:
NARA [144]2 years ago
8 0
The Answer is
X=10

Explanation:
You might be interested in
If you are given the following stem and leaf display and asked to construct a frequency distribution chart, what would be the wi
Nuetrik [128]

Answer:

Width of intervals: 8

Step-by-step explanation:

We first look at how data is represented in a stem-leaf diagram.

Any number of the left (before -) is the stem and all numbers on right (after -) are the leaves. Each combination of stem and leaf represents one number. For example: 1 - 332 represents: 13, 13, 12.

Our data is as follows:

13, 13, 12, 24, 25, 31, 31, 35, 37, 42, 43, 41, 52, 51, 51, 52

To calculate the width of the frequency distribution chart, we have the following formula:

Class\ width = \frac{Range}{Number\ of\ classes}

The range of any data set = Maximum value in the data set - Minimum value in the data set

Maximum value in this case as seen from the data is 52 and minimum is 12.

Range = 52 - 12 = 40

Since we had only 5 stems in the data, we shall use that as the number of classes required in the frequency distribution chart.

Class\ width = \frac{40}{5}  = 8

Hence, the class width in this data set will be 8.

To make the intervals, we begin from the minimum value and add 8 to it. The intervals will be:

12 - 20

20 - 28

28 - 36

36 - 44

44 - 52

Observe, that all the values of the stem lie within each interval.

For example, there are 3 values for stem 1: 12, 13, 13 and each lie in the first interval 12 - 20.

Next, the values of stem 2 are 24 and 25. Each of these value lie in the second interval 20 - 28; and henceforth.

8 0
3 years ago
Help me asap plssss !! will crown brainliest !!
Finger [1]

Answer: 82

Step-by-step explanation:

5 0
3 years ago
4. Is the following definition of perpendicular reversible? If yes, write it as a true biconditional.
artcher [175]

<span>Is the following definition of perpendicular reversible? If yes, write it as a true biconditional.</span>

Two lines that intersect at right angles are perpendicular.

<span>A. The statement is not reversible.   </span>

<span>B. Yes; if two lines intersect at right angles, then they are perpendicular.   </span>

<span>C. Yes; if two lines are perpendicular, then they intersect at right angles.   </span>

<span>D. Yes; two lines intersect at right angles if (and only if) they are perpendicular.</span>



Your Answer would be (D)

<span>Yes; two lines intersect at right angles if (and only if) they are perpendicular.


</span><span>REF:    2-3 Biconditionals and Definitions</span>
6 0
3 years ago
Read 2 more answers
Given the function defined below, what is the value of the 4th term?
MakcuM [25]

Answer:

The 4 t h term is   f(4)   = 143

Step-by-step explanation:

<em>Explanation</em>:-

Given  function f(1) = -4

Given 'nth' term is  f(n) = -3f(n-1) +5

Put n =2         <em> f(2) = -3 f(2-1) +5</em>

                             = -3 f(1) +5

                             = -3 (-4) +5

                             = 12 +5

                       f(2) = 17

put n= 3      

                         f(n) = -3f(n-1) +5  

                      <em>   f(3) = -3 f(3-1) +5</em>

                            = -3f(2) +5

                           = -3(17) +5

                           = -51+5

                      f(3) = -46

Put n=4

                  f(n) = -3f(n-1) +5

               <em>  f(4)  = -3f(4-1) +5</em>

<em>                  f(4)  = -3f(3)+5</em>

                f(4)   = -3(-46)+5

                f(4)   = 138 +5

                f(4)   = 143

<u><em>Final answer</em></u>:-

<em>The 4 t h term is   f(4)   = 143</em>

         

6 0
2 years ago
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
marissa [1.9K]

Complete question:

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

what is the area of the sector?

Answer:

The area of the sector = \frac{\pi}{2} square units

Step-by-step explanation:

To find the area of the sector of a circle, let's use the formula:

A = \frac{1}{2} r^2 \theta

Where, A = area

r = radius = 3

\theta = \frac{1}{9}\pi

Substituting values in the formula, we have:

A = \frac{1}{2}*3^2* \frac{1}{9}\pi

A = \frac{1}{2}*9* \frac{1}{9}\pi

A = 4.5 * \frac{1}{9}\pi

A = \frac{\pi}{2}

The area of the sector = \frac{\pi}{2} square units

8 0
3 years ago
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