3 = 3/4(b - 8)
Switch sides
3/4(b - 8) = 3
Next, multiply both sides by 4
4 * 3/4(b - 8) = 3 * 4
Then simplify,
3(b - 8) = 12
Next, divide both sides by 3
3(b - 8)/3 = 12/3
Then, simplify
b - 8 = 4
Then, add 8 to both sides
b - 8 + 8 = 4 + 8
Simplify, b = 12
I think that the baby would weight 18 pounds if her weight doubles in six months
Let's go through the steps of factoring that Venita should take.
1.) Find the greatest common factor (GCF). We only have two terms, so that makes it pretty easy.
32 = 1, 2, 4, 8, 16, 32
8 = 1, 2, 4, 8
The greatest common factor of 32 and 8 is 8. We can also factor out a <em>b</em> since that term appears in each part of the original expression. The GCF and variable should go on the outside of the parentheses.
8b( )
2.) Now let's figure out what should go in the middle of the parentheses. To do this, use the original expression and divide each term. This is written in the parentheses.
32ab ÷ 8b = 4a
8b ÷ 8b = 1
This would then result in the factored expression 8b(4a - 1). You can always check this by using the distributive property. Distribute 8b out to both expressions:
8b x 4a = 32ab
8b x 1 = 8b
32ab - 8b is the expression she started with, so your factored expression works!
Now that we went through the steps to solve the factored expression, let's check her answer. The only difference between Venita's and ours is that she has 0 as the second term while we have a 1. It seems that she had subtracted the GCF from the second term instead of dividing.
Answer:
It's f(x)=10x+8
Step-by-step explanation:
Because it says every hour not every half hour and the graph changes by 0.5 instead of 1 so m would equal 10
Answer:
The explicit formula that can be used is 
The account's balance at the beginning of year 3 is 
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above
