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Aneli [31]
4 years ago
5

What is the solution set? −2.8x+5.6<8.4

Mathematics
2 answers:
GaryK [48]4 years ago
7 0
Step 1: Subtract 5.6 from both sides.<span><span><span><span>
−<span>2.8x</span></span>+5.6</span>−5.6</span><<span>8.4−5.6</span></span><span><span>
−<span>2.8x</span></span><2.8

</span><span>Step 2: Divide both sides by -2.8.

-2.8x/-2.8<2.8/-2.8

The answer is x > -1





Hope this helped :)


</span>

Andreas93 [3]4 years ago
4 0

Answer: x >-1

Step-by-step explanation:

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A cylinder has a circular base with a diameter of 12 ft the height of the cylinder is 4 feet what is the volume of the cylinder
Murrr4er [49]

Answer:

452\ ft^{3}

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

we have

r=12/2=6\ ft ----> the radius is half the diameter

h=4\ ft

substitute the values

V=(3.14)(6^{2})(4)=452\ ft^{3}

5 0
4 years ago
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jolli1 [7]

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6 0
3 years ago
Use the given information to write the equation of the parabola.
m_a_m_a [10]

Answer:

x² = -2y

Step-by-step explanation:

The focus is p away from the vertex, and so is the directrix.

To find the equation of the parabola, we must first determine if the parabola is horizontal or vertical.

  • Horizontal parabola [Standard form]: (y – k)² = 4p(x – h)
  • Vertical parabola [Standard form]: (x – h)² = 4p(y – k)

If the parabola is vertical, the directrix, and focus will have the same x value but different y value compared to the vertex (h, k). You can also tell if the directrix in in the form y = k – p, and if the focus is in the form (h, k + p).

Likewise, if the parabola is horizontal, the directrix, and focus will have the same y value but different x value compared to the vertex (h,k) . You can also tell if the directrix is in the form x = h – p, and if the focus is in the form (h + p, k).

For this problem, given that the vertex is at the origin (0,0), and that the focus is at the point (0, -½).

You can tell that the x value is the same for the vertex, and focus so this must be a vertical parabola. Because this is a vertical parabola, we can use the form mentioned as earlier (x – h)² = 4p(y – k).

If h = 0, and k = 0, the p value must be the difference between the k of the vertex, and the k of the focus: -½ - 0 → -½.

Now we can just plug in our known information to derive the equation!

h = 0, k = 0, p = -½ → (x - h)² = 4p(y - k) →

(x - 0)² = 4(-½)(y - 0) → x² = -2(y - 0) →

x² = -2y.

Also p = 1/4a, if you are wondering.

So because this is a vertical parabola, x² = -2y is generally the same as y = -1/2x² in standard quadratic form. I just like to think of the horizontal parabola as an inverse quadratic because it is like reflecting over the line y = x.

8 0
3 years ago
Read 2 more answers
H(t)=480t-16t^2<br><br> solve for t <br><br> PLEASE SHOW WORK
Andru [333]

Answer:

x = √30 or -√30

Step-by-step explanation:

480 - 16x^2 = 0

divide both sides by 16

30 - x^2 = 0

-x^2 + 30 = 0

-x^2 = -30

X^2 = 30

x = ± √30

x = √30 or -√30

7 0
3 years ago
Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0
3 years ago
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