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3 years ago

the equation for a dog weight in pound (y) based on the number of burgers ir eats (x) seen in the equation below y=0.5x × 12

Mathematics

1 answer:

Iteru [2.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

Your Welcome

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Solve 100y + 50x = 200

liq [111]

The answer to your question is x=-2y+4

7 0

3 years ago

Read 2 more answers

When an equation is written in the form Ax + By = C [picture attached] help pls

balu736 [363]

Answer:

B. Standard Form

Step-by-step explanation:

Ax+By=C is in Standard Form of a linear function

8 0

3 years ago

If the measure of two angles in a triangle are 60 and 100 degrees, what is the measure of the third angle? a. 20 degrees) b. 50

bonufazy [111]

Answer:

A. 20 degrees

Step-by-step explanation:

<u>All triangles have 180 degrees in total !</u>

using that info,

100+60= 160

180-160 = 20

4 0

3 years ago

What is the area of this trapezoid (the right leg says 8 btw)

alekssr [168]

The answers have square roots among the choices so we probably shouldn't use that calculator button.

We can't just apply the area of the trapezoid formula

$A = \frac 1 2(b + t) h$

where b is the bottom base, t the parallel top, and h the height, because we don't know the top t.

It will be 10 less the leg of that right triangle, which we calculate as

$l = \sqrt{8^2 - (4\sqrt{3})^2} = \sqrt{64 - 48} = \sqrt{16}=4$

Now we can apply the trapezoid formula. We have

$b = 10, \qquad t=10-4=6, \qquad h= 4\sqrt{3}$

$A = \frac 1 2(b + t) h = \frac 1 2 (10 +6)(4 \sqrt{3}) = 32 \sqrt{3}$

Choice b

7 0

3 years ago

The outcome X of an experiment has only two possible values, X= 4 and X= 5. Given that the expected outcome E(X)= 4.2, find P(X=

alukav5142 [94]

Answer:

P(X=5) = 0.2

Step-by-step explanation:

Expected outcome, E(x) = ∑XP(X)

∑ = Summation

X = outcomes

P(X) = probability of an outcome

E(X) = (4*P(X=4)) + (5*P(X=5)) = 4.2

So, 4P(X=4) + 5P(X=5) = 4.2 ... equation 1

But the sum of probabilities = 1

That is, P(X=4) + P(X=5) = 1 ... equation 2

Thus, we have the following system of equations

4P(X=4) + 5P(X=5) = 4.2 ... equation 1

P(X=4) + P(X=5) = 1 ... equation 2

Multiply equation 2 by 4

4*P(X=4) + 4*P(X=5) = 4*1

4P(X=4) + 4P(X=5) = 4 ... equation 3

4P(X=4) + 5P(X=5) = 4.2 ... equation 1

4P(X=4) + 4P(X=5) = 4 ... equation 3

Subtract equation 3 from 1

4P(X=4) - 4P(X=4) + 5P(X=5) - 4P(X=5) = 4.2 - 4

P(X=5) = 0.2

3 0

3 years ago