Answer: See Explanation
Step-by-step explanation:
The price elasticity of demand will be calculated as:
q = 860 − 20p.
dq/do = -20
p = 38
Elasticity E(p) = (p/q) × dq/dp
= [38 /(860 - 20p)] × (20)
=38 × 20/(860 - 760)
= 7.6
Therefore, the price elasticity of demand when the price is $38 per orange is 7.6
Revenue = price × quantity
= p × q
= p × (860 − 20p)
= 860p - 20p²
Differentiating with respect to p
= 860 - 40p
40p = 860
p = 860/40
p = 21.50
Maximum Revenue = 860p - 20p²
= 860(21.50) - 20(21.50)²
= 18490 - 9245
= 9245
Answer:
(A, B) = (-3, -129).
Step-by-step explanation:
First convert the first equation to slop-intercept form:
x + 5y = 7
5y = -x + 7
y = -0.2x + 1.4
The slope is -0.2 so the slope of the line perpendicular to this line has slope
-1/ -0.2 = 5.
Now, converting the second equation to slope-intercept form:
15x + Ay = B
Ay = -15x + B
y = (-15/A)x + B/A
So the slope -15/A = 5 so A = -3.
So y = 5x + B/-3
Substituting the point (-8, 3)
3 = 5(-8) + B/-3
B/-3 = 43
B = - 129.
Answer:
The weight of one rooster is 3 Kg and the weight of one hen is 2 Kg
Step-by-step explanation:
<u><em>The question in English is</em></u>
Two roosters weigh as much as 3 chickens. Eight roosters and 9 hens weigh 42 kg. How much does a rooster weigh and how much does a hen weigh, knowing that all roosters have the same weight, respectively the hens weigh the same.
Let
x ----> the weight of one rooster in kilograms
y ----> the weight of one hen in kilograms
we know that
------> equation A
----> equation B
Solve the system by graphing
Remember that
The solution of the system of equations is the intersection point both graphs
The solution is the point (3,2)
see the attached figure
therefore
The weight of one rooster is 3 Kg and the weight of one hen is 2 Kg
Answer: 36 
Step-by-step explanation: I took the test and the person that answered 6 is wrong because it's not even on the test :T
The correct answer is m<1