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MrRa [10]
3 years ago
13

The temperature fell from 0 Degrees Fahrenheit to 15 and one-half Degrees Fahrenheit below 0 in 5 and three-fourths hours. Wen t

ried to find the change in temperature per hour. Her work is shown below. Negative 15 and one-half divided by 5 and three-fourths = negative StartFraction 31 over 2 EndFraction divided by StartFraction 23 over 4 EndFraction = negative StartFraction 31 over 2 EndFraction times StartFraction 23 over 4 EndFraction = Negative StartFraction 713 over 8 EndFraction
Mathematics
2 answers:
Kryger [21]3 years ago
5 0

Answer:

The correct answer will be:

-\dfrac{62}{23}

Step-by-step explanation:

It is given that :

Initial temperature, T_1 = 0^\circ F

Final temperature,

T_2 = -15\dfrac{1}{2}^\circ F\\\Rightarrow T_2 = -\dfrac{15\times 2+1}{2} ^\circ F\\\Rightarrow T_2 = -\dfrac{31}{2} ^\circ F

Time taken :

5\dfrac{3}{4}\ hrs = \dfrac{5 \times 4+3}{4}\ hrs = \dfrac{23}{4}\ hrs

Change in temperature per hour:

\dfrac{\text{Difference of temperature}}{\text{Total Time Taken}}\\\Rightarrow \dfrac{T_2-T_1}{\text{Total Time Taken}}

Putting the values of temperatures and time:

\dfrac{\dfrac{-31}{2}-0}{\dfrac{23}{4}}\\\Rightarrow \dfrac{\dfrac{-31}{2}}{\dfrac{23}{4}}\\\Rightarrow \dfrac{-31 \times 4}{2 \times 23}} \text{---- Error done by Wen at this step}\\\Rightarrow \dfrac{-31 \times 2}{23}}\\\Rightarrow \dfrac{-62}{23}}

The error done by Wen was during calculating the values of fraction.

So, the correct answer is :\frac{-62}{23}} instead of \frac{-713}{8}

Nookie1986 [14]3 years ago
5 0

Answer:

C. Wen did not take the reciprocal of the divisor

Step-by-step explanation:

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We know that 20% of the first type of juice is pure fruit juice and 45% of second type of juice is pure fruit juice.

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3 years ago
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3 0
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andrew-mc [135]
\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

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Write the divide fraction horizontally:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

-----------------------------------------------------------------------------------
Factorise the numerators and denominators when possible:
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= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

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Convert the divide fraction to multiplication fraction
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= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

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Cancel the factors
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= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

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Combine to single fraction
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= \dfrac{1}{4(x+2)^2}



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Step-by-step explanation:

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3 years ago
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Answer:

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