For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that 
is such that
Obviously, both limits are 0, so 
is indeed continuous at 
.
Now, for to be differentiable everywhere, its derivative 
must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:
and at this time, we don't know what's going on at , so we omit that case. We want to be continuous, so we require that
from which it follows that 
.
Answer:
C. is irrational D. is non existing.
Step-by-step explanation:
C is an infinite number that never repeats which makes it irrational, while there is no answer to D; it doesn't exist.
hope this helps
Answer:
B
Step-by-step explanation:
If you're concerned with the points -2 and -5, you would be looking for a number line with those points plotted on it. The only one is ...
number line B
Answer:
x = 25
Step-by-step explanation:
It is given that,
JK =5x+17,
KL = x -1,
JL=7x-9
We need to find the range of possible values for x.
It can be assumed that K is a mid point of JL.
JL = JK + KL
Putting all the values,
7x-9 = 5x+17 + x -1
Taking like terms together,
7x-5x-x = 17-1+9
x = 25
So, the value of x is 25.
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