Please consider the attached file.
We can see that triangle JKM is a right triangle, with right angle at M. Segment KM is 6 units and segment MJ is 3 units. We can also see that KJ is hypotenuse of right triangle.
We will use Pythagoras theorem to solve for KJ as:
Now we will take positive square root on both sides:
Therefore, the length of line segment KJ is and option D is the correct choice.
The closest point above on this line is (0,9)
You can find this by using the rise over run method. Since the slope is -2, we can move to the next whole number point by observing the fraction 2/-1.
Rise = 2
Run = -1
If you start on the point (1,7) and rise two, it will bring you to (1,9), then you have to move back one space (or run) to (0,9).
Answer:
1929r9fij1j2jed8f82u2hfisj
Step-by-step explanation:
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