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Zarrin [17]
3 years ago
5

LAST QUESTION I NEED HELP WITH!!! THANKS<3

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

  99.38 grams

Step-by-step explanation:

The given information can be translated to the exponential function ...

  q = 50·0.98^(t -34) . . . . . t in days

Then for t=0, we have ...

  q = 50·0.98^(-34) ≈ 99.38 . . . . grams

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Carson drives to school the same way each day and there are two independent traffic lights on his trip to school. He knows that
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Answer:The correct answer is A, 14%.

Step-by-step explanation:

All you have to do is take the 30% chance of you HAVING to stop at the first light and find the chance that you won't have to stop at the first light, which is 70%, or .7. Then you take the chance of having to stop at the second light which is 80%, and find the probability of NOT having to stop there, which is 20%, or .2. Then you multiply the probabilities of not having to stop, which equals to .14.

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If 8 family members choose to play "Secret Santa," how many different ways can the names be paired?
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300,000,000 or three hundred million

Step-by-step explanation:

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DENIUS [597]

Answer:

Ask in English then I can help u

4 0
3 years ago
A performer in a circus is fired from a cannon as a ``human cannonball'' and leaves the cannon with a speed of 16.4 m/s. The per
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Answer:

1195.22N.

Step-by-step explanation:

Mass: m =82.6 kg

Velocity: v= 16.4m/sec.

Distance: d = 9.29 metres.

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Force = (mass x acceleration) = (82.6 x 14.47) = 1195.22N.

3 0
3 years ago
A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
3 years ago
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