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2 years ago

8x - 3(2x - 4) * - 9

Mathematics

2 answers:

Zinaida [17]2 years ago

8 0

Answer:

x = 54/31

Step-by-step explanation:

Solve for x:

8 x + 27 (2 x - 4) = 0

27 (2 x - 4) = 54 x - 108:

54 x - 108 + 8 x = 0

Grouping like terms, 54 x + 8 x - 108 = (8 x + 54 x) - 108:

(8 x + 54 x) - 108 = 0

8 x + 54 x = 62 x:

62 x - 108 = 0

Add 108 to both sides:

62 x + (108 - 108) = 108

108 - 108 = 0:

62 x = 108

Divide both sides of 62 x = 108 by 62:

(62 x)/62 = 108/62

62/62 = 1:

x = 108/62

The gcd of 108 and 62 is 2, so 108/62 = (2×54)/(2×31) = 2/2×54/31 = 54/31:

Answer: x = 54/31

trapecia [35]2 years ago

4 0

Answer:

62x - 108

Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers

If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what

Lisa [10]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}$

$\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}$

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