Answer:
(x+1)^2+(y+1)^2=13
Step-by-step explanation:
Equation of a circle: (x – h)^2 + (y – k)^2 = r^2
center: (-1, -1)
radius: sqrt(6^2+4^2)/2=sqrt(52)/2=2sqrt(13)/2=sqrt(13)
Substitute those values in to get
(x+1)^2+(y+1)^2=13
We will be using the Point Slope formula which is 
The information we are given is that m = -4 and the point is (2,-5), so we can input it into the equation.

This simplifies into 
Then we can subtract 5 from each side to get the answer:

We know that:

Then:

Therefore:

Simplifying the above result we get:

Answer:
Answer:
A) Not mutually exclusive
Step-by-step explanation:
Given



Required
Determine if they are mutually exclusive or not
Mutually exclusive are defined by:

So, we have:

Take LCM


By comparing:
---- Calculated
---- Given
We can conclude that A and B are not mutually exclusive because:
