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3 years ago

When an object falls freely, the formula for the distance it falls is d= 4.9t^2 where d is

Mathematics

2 answers:

SVETLANKA909090 [29]3 years ago

4 0

Answer:

a) 122.5 meters

b) 10 seconds

Step-by-step explanation:

german3 years ago

3 0

Answer:

a) 122.5 m ; b) 10 s

Step-by-step explanation:

Just use the given equation and plug in what you know.

d = 4.9t^2

d = 4.9(5^2)

d = 4.9 * 25

d = 122.5 m

d = 4.9t^2

490 = 4.9t^2

100 = t^2

t = 10 s

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Answer:

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Answer:

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Step-by-step explanation:

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Yuki888 [10]

Answer:

a) $t_{crit}= 1.34$

b) $t_{crit}=-2.539$

c) $t_{crit}=\pm 2.228$

Step-by-step explanation:

Part a

The significance level given is $\alpha=0.1$ and the degrees of freedom are given by:

$df = n-1= 15$

Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:

$t_{crit}= 1.34$

Part b

The significance level given is $\alpha=0.01$ and the degrees of freedom are given by:

$df = n-1= 20-1=19$

Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:

$t_{crit}=-2.539$

Part c

The significance level given is $\alpha=0.05$ and $\alpha/2 =0.025$ and the degrees of freedom are given by:

$df = n-1= 11-1=10$

Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:

$t_{crit}=\pm 2.228$

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