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mash [69]
2 years ago
10

Please solve: m²j³j⁵/m⁸j⁻²m³

Mathematics
1 answer:
Alecsey [184]2 years ago
7 0

Step-by-step explanation:

first, simplify each part.

m²j^8

m¹¹j^-2

now put them together:

(m²j^8)÷(m¹¹j^-2)=m^-9 j^10

if anything is unclear, ask freely.

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11x-3=x-13 (solve for x)
omeli [17]
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----    -----
10      10 
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8 0
3 years ago
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Hitman42 [59]

Answer:

75

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6 0
2 years ago
Replace ∗ with a monomial so that the derived equality will be an identity: (15y + ∗)2 = 225y2+12x3y+0.16x6
kobusy [5.1K]

Answer:

<u>∗ = 0.4x³</u>

Step-by-step explanation:

(15y + ∗)² = 225y²+12x³y+0.16x⁶

<u>Note:</u>

225y² = 15y * 15y = (15y)²

12x³y = 2 * 15y * 0.4x³

0.16x⁶ = 0.4x³ * 0.4x³ = (0.4x³)²

So, by factoring the right hand side:

225y²+12x³y+0.16x⁶ = (15y + 0.4x³)²

By comparing the left hand side with (15y + 0.4x³)²

<u>So, ∗ should be replaced with the monomial 0.4x³</u>

6 0
3 years ago
Can anyone help me with this?<br> Thank you
Sergeeva-Olga [200]

1. 3,6

2. 5,6

3. 4,5

(branliest will be appreciated and thanks)

8 0
2 years ago
Read 2 more answers
What kind of problem is this?
strojnjashka [21]
4x - 7 < 17
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Solution Set: (6, ∞) and {x|x < 6}
8 0
3 years ago
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