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3 years ago

{20 points}

1 answer:

6 0

Midpoint formula is ( (x₁+x₂) / 2, (y₁+y₂) / 2 )

So that would be ( (9-1) / 2, (8-2) / 2 ) = ( 8 / 2, 6 / 2 ) = (4, 3)

Final answer: (4, 3)

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Geometry, help please ! :)

Dovator [93]

The bottom rectangle is 52 ft by 27 ft.

The top rectangle is 30 ft by 17 ft (calculated as 57 ft - 27 ft - 13 ft = 17 ft).

The connector rectangle is 13 ft by 9 ft (calculated as 30 ft - 21 ft = 9 ft).

total area = 52 ft * 27 ft + 30 ft * 17 ft + 13 ft * 9 ft

total area = 1404 ft^2 + 510 ft^2 + 117 ft^2

total area = 2031 ft^2

weight = 2031 ft^2 * 12 lb/ft^2

weight = 24,372 lb

4 0

3 years ago

GREATEST COMMON FACTOR OF 8 OF 36

Mekhanik [1.2K]

Answer:

Step-by-step explanation:

greatest common factor means the largest positive number that can divide both terms

if you divide 8 by 4 = 2

and if you divide 36 by 4 = 9

8 0

3 years ago

Read 2 more answers

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago

After Halloween, supermarkets put Halloween candy on sale. The first week after Halloween, the manager marked the candy down 40%

OLEGan [10]

Answer:15

Step-by-step explanation:

Hi I'm lala my sister does this alot I wanna retry it did I get it right I guessed

4 0

3 years ago

Someone plz answer this o need it done

viva [34]

I believe the answer is B

please give brainliest if helped :)

4 0

3 years ago