1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lelu [443]
3 years ago
6

Suppose a 96.10 kg hiker has ascended to a height of 1841 m above sea level in the process of climbing Mt. Washington. By what p

ercent has the hiker's weight changed from its value at sea level as a result of climbing to this elevation? Use g=9.807 m/s2 and R=6.371×106 m . Keep four significant figures in your weight calculation to find the percent difference, and enter your answer as a positive value.
Physics
1 answer:
lbvjy [14]3 years ago
6 0

Answer:

0.029%

Explanation:

Weight on the surface is given by,

F_W = mg = (96.1Kg)(9.8m/s^2)=941.78N

The acceleration due to gravity at given height is,

g_h=\frac{gR^2}{R+h^2}

The weight in another height is equal to

F_h=mg_h

F_h= m*\frac{gR^2}{R+h^2}

F_h = \frac{F_WR^2}{(R+h)^2}

F_h=\frac{(941.78)(6.371*10^6)}{(6.371*10^6+1841)}

F_h = 941.50N

The change of the Weight is,

\frac{F-F_h}{F}*100=\frac{941.78-941.50}{941.78}*100=0.029\%

You might be interested in
A car is traveling at 114 m/s and changes its velocity to 77 m/s in 9 sec.
suter [353]

Answer:

<u>Given</u><u> </u><u>-</u>

  • Initial Velocity, u = 114 m/s
  • Final velocity, v = 77 m/s.
  • Time taken, t = 9 sec.

<u>To</u><u> </u><u>find</u><u> </u><u>-</u><u> </u>

  • Acceleration of the car.

<u>Solu</u><u>tion</u><u> </u><u>-</u>

Here, using the equation of motion v = u + at we can find the acceleration easily.

★ Here,

  1. V = Final velocity
  2. U = Initial Velocity
  3. A = Acceleration
  4. T = Time.

<u>Subs</u><u>tituting</u><u> </u><u>the</u><u> </u><u>values</u><u> </u><u>-</u>

→ 77 = 114 + a(9)

→ 9a = 114 - 77

→ 9a = 37

→ a = 37/9

→ a = 4.1 m/s

<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>accele</u><u>ration</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>car</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>4</u><u>.</u><u>1</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>

5 0
3 years ago
The speed of a rocket just after being launched is 12 m / s.
drek231 [11]

This question involves the concepts of the equations of motion, kinetic energy, and potential energy.

a. The kinetic energy of the rocket at launch is "3.6 J".

b. maximum gravitational potential energy of the rocket is "3.6 J".

<h3>a. KINETIC ENERGY AT LAUNCH</h3>

The kinetic energy of the rocket at launch is given by the following formula:

K.E=\frac{1}{2} m v_i^2

where,

  • K.E = initial kinetic energy = ?
  • m = mass of rocket = 0.05 kg
  • v_i = initial speed = 12 m/s

Therefore,

K.E=\frac{1}{2}(0.05\ kg)(12\ m/s)^2

K.E = 3.6 J

<h3>b. MAXIMUM GRAVITATIONAL POTENTIAL ENERGY</h3>

First, we will use the third equation of motion to find the maximum height reached by rocket:

2gh=v_f^2-v_i^2

where,

  • g = -9.81 m/s²
  • h = maximum height = ?
  • vf = final speed  = 0 m/s

Therefore,

2(-9.81 m/s²)h = (0 m/s)² - (12 m/s)²

h = 7.34 m

Hence, the maximum gravitational potential energy will be:

P.E = mgh

P.E = (0.05 kg)(9.81 m/s²)(7.34 m)

P.E = 3.6 J

Learn more about the equations of motion here:

brainly.com/question/5955789

4 0
2 years ago
13 Henry Wadsworth Longfellow, John Greenleaf Whittier, Oliver Wendell Holmes, and James Russel Lowell were known as​
Snowcat [4.5K]

Answer:

The fireside poets also known as the schoolroom or household poets Explanation:

i helped my sis with it and got it correct

5 0
2 years ago
Whose famous conjecture is paraphrased as "space, time, and matter"?
GaryK [48]

The person who came up with this conjecture was Albert Einstein

7 0
3 years ago
Read 2 more answers
The horizontal surface on which the 2.0 - kg block slides is frictionless. The speed of the block before it touches the spring i
vlabodo [156]

Answer:

0.918 seconds

Explanation:

M = 2kg

V = 9.0 m/s

g = 9.8 m/s

F = Mg cosΘ

Θ = 0°

But F = Ma

a = v / t

F = m*v / t

Mv / t = mg cos0

V / t = g

t = v / g

t = 9.0 / 9.8

t = 0.918s

5 0
3 years ago
Other questions:
  • An airplane pilot wishes to fly due west. A wind of 80.0 km/h (about 50 mi/h) is blowing toward the south. (a) If the airspeed o
    7·2 answers
  • A jet plane that has a minimum takeoff speed of 80 m/s begins 70 m from one end of the runway. The runway is 2200 m long. What a
    9·1 answer
  • What subtomic particle takes electric charge in friction​
    7·1 answer
  • The moon’s rotational period and revolution period are equal. What is the result of this? Enter your answer in the space provide
    8·1 answer
  • In which direction does a buoyant force act on an object?
    8·1 answer
  • What colours do you see in a solar spectrum? Which colour is the closest to the bright spot?Which colour is the farthest from th
    13·1 answer
  • Draw 2 lights in parallel in series with 1 light.
    10·1 answer
  • A 1.6 Kg bird that is flying through the air has 220 J of kinetic energy. How fast is the bird flying?
    15·1 answer
  • What is a hedge in science​
    8·1 answer
  • A 783kg elevator rises straight up 164 meters. What is the potential energy of the elevator?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!