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3 years ago

What energy transformation takes place when an object is pushed up an inclined plane?

Physics

2 answers:

sweet [91]3 years ago

8 0

Answer:

There are two main phases or positions for any object to have in order to posses some energy, and that is either due to its height,H or due to the motion in which the body performs displacement from point A to B. So, lets say there is a object having a specific mass, m inside any region.
Then if we displace that very object from its initial point to the final point of rest at a certain, during these two points there is kinetic energy(K.E) for the body to have, after which the whole scenario changes when it comes to a rest position. Now, the parameters are much more changed for the object and its because of the height,h and the gravity that is applying on the object placed at a certain height,h. So, we got the very equation for calculating the potential energy(P.E) of that body or object, which is P.E= (m)×(g)×(h).
And at any certain height,h the factor of gravity comes into play which brings more energy,E into the whole system of the body and to acquire a certain possession of energy inside the space.

Fofino [41]3 years ago

5 0

When you are pushing an object up an inclined plane, the object is gaining gravitational potential energy as it is gaining height. The kinetic energy of the object decreases and converts into that potential energy as you go up. When you have stopped, all of the kinetic energy of the object has fully been converted to gravitational potential energy.

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In 2h2so4, the number of hydrogen atoms is 1 2 4 8

pishuonlain [190]

C.) In this, number of Hydrogen atoms is 4

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3 years ago

A flat sheet of ice has a thickness of 2.20 cm. It is on top of a flat sheet of crystalline quartz that has a thickness of 1.50

kolezko [41]

Answer:

$Distance_{vaccum}=5.19cm$

Explanation:

The speed of light in these mediums shall be lower than that in vacuum thus the total time light needs to cross both the media are calculated as under

Total time = Time taken through ice + Time taken through quartz

Time taken through ice = Thickness of ice / (speed of light in ice)

$T_{ice}=\frac{2.20\times 10^{-2} \times \mu _{ice}}{V_{vaccum}}$

$T_{quartz}=\frac{1.50\times 10^{-2} \times \mu _{quartz}}{V_{vaccum}}$

Thus in the same time the it would had covered a distance of

$Distance_{vaccum}=Totaltime\times V_{vaccum}\\\\Distance_{vaccum}=10^{-2}[2.20\mu _{ice+1.50\mu _{quartz}}]$

we have

$\mu _{ice}=1.309\\\\\mu _{quartz}=1.542$

Applying values we have

$Distance_{vaccum}=10^{-2}[2.20\times 1.309+1.50\times 1.542]$

$Distance_{vaccum}=5.19cm$

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3 years ago

A girl runs south 10 meters then turns around and walks back 3 meters

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Answer:

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3 years ago

In the reaction at Blood Falls, iron and oxygen combine to form iron oxide, which is called rust (water is also present). The re

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Reactant is a substance that is in a chemical reaction. Product is a substance that is produced by the chemical reaction. A chemical change that you are familiar with isrust. In this chemical reaction, oxygen and iron, which are the reactants,combine to form a product called iron oxide(rust)
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3 years ago

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A truck is moving around a circular curve at a uniform velocity of 13 m/s. If the centripetal force on the truck is 3,300 N and

Paladinen [302]

Answer: Option B.

Since here the truck is moving on a circular track, it will experience centripetal force.

F(centripetal) = m × acc
or
$r = \frac{m v^{2}}{F}$

where r is the radius of the track.
m is the mass of truck
v is the speed of the truck.
Given: v = 13 m/s
m = 1,600 kg
F = 3300 Newton

To find = radius of track=?
$r = \frac{m v^{2} }{F}$
$r = \frac{1600*13*13}{3300}$
r = 81.94 m
Therefore, radius of track is 81.94 m

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3 years ago

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