All categories

3 years ago

What energy transformation takes place when an object is pushed up an inclined plane?

Physics

2 answers:

sweet [91]3 years ago

8 0

Answer:

There are two main phases or positions for any object to have in order to posses some energy, and that is either due to its height,H or due to the motion in which the body performs displacement from point A to B. So, lets say there is a object having a specific mass, m inside any region.
Then if we displace that very object from its initial point to the final point of rest at a certain, during these two points there is kinetic energy(K.E) for the body to have, after which the whole scenario changes when it comes to a rest position. Now, the parameters are much more changed for the object and its because of the height,h and the gravity that is applying on the object placed at a certain height,h. So, we got the very equation for calculating the potential energy(P.E) of that body or object, which is P.E= (m)×(g)×(h).
And at any certain height,h the factor of gravity comes into play which brings more energy,E into the whole system of the body and to acquire a certain possession of energy inside the space.

Fofino [41]3 years ago

5 0

When you are pushing an object up an inclined plane, the object is gaining gravitational potential energy as it is gaining height. The kinetic energy of the object decreases and converts into that potential energy as you go up. When you have stopped, all of the kinetic energy of the object has fully been converted to gravitational potential energy.

You might be interested in

A student uses 60 Newtons of force to climb 18 meters in 6 seconds. Calculate her Power.

puteri [66]

Answer:

Explanation:

P=W/T

T=6sec

W=?

F=60N

S=18m

W=F X S. .s indicate displacement

W=60x18

W=108

So p=108 j/6sec

P=15watt

5 0

3 years ago

What would be the answer for this and how?

Veronika [31]

Answer:

B. 6 cm

Explanation:

First, we calculate the spring constant of a single spring:

$k = \frac{F}{\Delta x}\\$

where,

k = spring constant of single spring = ?

F = Force Applied = 10 N

Δx = extension = 4 cm = 0.04 m

Therefore,

$k = \frac{10\ N}{0.04\ m}\\k = 250\ N/m\\$

Now, the equivalent resistance of two springs connected in parallel, as shown in the diagram, will be:

$k_{eq} = k + k\\k_{eq} = 2k = 2(250\ N/m)\\k_{eq} = 500\ N/m\\$

For a load of 30 N, applying Hooke's Law:

$\Delta x = \frac{F}{k_{eq}}\\\\\Delta x = \frac{30\ N}{500\ N/m}\\\\\Delta x = 0.06\ m = 6\ cm\\$

Hence, the correct option is:

7 0

3 years ago

Toy car in a science experiment covers 1.6 meters in half a second. If a the car travels at a steady speed, how far will it go i

Tanzania [10]

The answer is D. 32 m.

The simple equation that connects speed (v), time (t), and distance (d) can be expressed as:
$v= \frac{d}{t}$ ⇒ $d=v*t$

It is given:
$v = \frac{1.6m}{0.5s} = \frac{1.6m*2}{0.5s*2}= \frac{3.2m}{1s} = 3.2 m/s$
t = 10 s
d = ?

So:
$d= v*t=3.2m/s*10s = 32m$

3 0

3 years ago

A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is

aniked [119]

1) At the moment of being at the top, the piston will not only tend to push the penny up but will also descend at a faster rate at which the penny can reach in 'free fall', in that short distance. Therefore, at the highest point, the penny will lose contact with the piston. Therefore the correct answer is C.

2) To solve this problem we will apply the equations related to the simple harmonic movement, hence we have that the acceleration can be defined as

$a = -\omega^2 A$