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ad-work [718]
3 years ago
6

ANSWER IN LESS THAN A MIN!! EASY!​

Physics
1 answer:
Romashka [77]3 years ago
3 0

Answer:

2 m/sec

Explanation:

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What is an electric circuit?
klemol [59]

<h3>Answer: any path that allows electrons to flow</h3>

An electrical circuit is a path in which electrons from a voltage or current source flow. ... The part of an electrical circuit that is between the electrons' starting point and the point where they return to the source is called an electrical circuit's "load".

7 0
3 years ago
Read 2 more answers
A 2 kg toy car moves at a speed of 5 m/s.<br> What is the kinetic energy of the car?
ANTONII [103]

Answer:

<h2>The answer is 25 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

KE =  \frac{1}{2}  \times 2 \times  {5}^{2}  \\  = 1 \times  {5}^{2}

We have the final answer as

<h3>25 J</h3>

Hope this helps you

5 0
3 years ago
A typical ceiling fan running at high speed has an airflow of about 1.85 ✕ 103 ft3/min, meaning that about 1.85 ✕ 103 cubic feet
densk [106]

Answer:

0.8726  m^3/s

Explanation:

We are to convert 1.85 x 10^3 ft^3/min to m^3/s

First, let us convert the numerator from ft3 to m3

1 ft3 = 0.0283 m3

Hence,

1.85 x 10^3 ft3 = 1.85 x 10^3 x 0.0283 m3

     = 52.355 m3

Now, let us convert the denominator from minutes to seconds

1 min = 60 sec

Therefore;

1.85 x 10^3 ft^3/min = 52.355/60  m^3/s

        = 0.8726  m^3/s

7 0
3 years ago
Two identical charges q placed 2.0 mapart exert forces of magnitude 4.0 N on each other What is the value of the charge q? a) q
katen-ka-za [31]

Answer:

c) 4.2*10^{-5}C

Explanation:

Coulomb's law says that the force exerted between two charges is inversely proportional to the square of distance between them, and is given by the expression:

F=\frac{kq_{1}q_{2}}{r^{2}}

where k is a proportionality constant with the value k=9*10^{9}\frac{Nm^{2}}{C^{2}}

In this case q_{1}=q_{2}=q, so we have:

F=\frac{kq^{2}}{r^{2}}

Solving the equation for q, we have:

kq^{2}=Fr^{2}

q^{2}=\frac{Fr^{2}}{k}

q=\sqrt{\frac{Fr^{2}}{k}}

Replacing the given values:

q=\sqrt{\frac{4.0N*(2.0m)^{2}}{9*10^{-9}\frac{Nm^{2}}{C^{2}}}}

q=4.2*10^{-5}C

3 0
3 years ago
Ezekiel pushes a 34 kg sled with 101 N for 8.0 m. How much work did he do on the sled?
Simora [160]

Answer: 810 J

Explanation: work W = F·s = 101 N · 8.0 m = 808 J

Force F = u mg = 101 N in which u is friction constant. Also mass is included in force.

7 0
2 years ago
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