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3 years ago

ANSWER IN LESS THAN A MIN!! EASY!

Physics

1 answer:

Romashka [77]3 years ago

3 0

Answer:

2 m/sec

Explanation:

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A long wire is known to have a radius greater than 4.0 mm and to carry a current uniformly distributed over its cross section. i

ollegr [7]

Magnetic field outside it due to long wire is given by

$B = \frac{u_o i}{2 \pi r}$

Magnetic field due to long wire inside wire at any point

$B = \frac{u_o i r}{2 \pi R^2}$

Now the ratio of two magnetic field is given by

$\frac{B_{in}}{B_{out}} = \frac{r_1/R^2}{1/r_2}$

$\frac{0.285}{0.200} = \frac{4*10}{R^2}$

$1.425 = \frac{40}{R^2}$

R = 5.3 mm

8 0

3 years ago

In a young's double-slit experiment, the angle that locates the second dark fringe on either side of the central bright fringe i

dem82 [27]

Answer:

(d/λ) = 17.67

Explanation:

Equation for double-slit:

d*sinθ = m*λ

Rearrange the equation

(d/λ) = m/(sinθ)

Since it is at the second dark fringe, m = 2

Therefore:

(d/λ) = 2/(sin(6.5)

(d/λ) = 17.67

6 0

3 years ago

What was the speed of a space shuttle that orbited Earth at an altitude of 1482 km?

gregori [183]

Answer:

v = 7121.3 m/s

Explanation:

As we know that the centripetal force for the space shuttle is due to gravitational force of earth due to which it will rotate in circular path with constant speed

so here we will have

$\frac{mv^2}{r} = \frac{GMm}{r^2}$

here we know that

r = orbital radius = 6370 km + 1482 km

$r = 7.852 \times 10^6 m$

also we know that

$M = 5.97 \times 10^{24} kg$

now we will have

$v^2 = \frac{(6.67 \times 10^{-11})(5.97 \times 10^{24})}{7.852 \times 10^6}$

$v^2 = 5.07 \times 10^7$

$v = 7121.3 m/s$

3 0

3 years ago

Read 2 more answers

A ball has mass of 140g. what is the force to accelerate the ball at 25m/s

Fittoniya [83]

We know, F = m * a

Here, m = 140 g = 0.140 Kg

a = 25 m/s2

It would be: F = 0.140 * 25 = 3.5 N

So your answer would be 3.5N

6 0

3 years ago

Read 2 more answers

You are on a ParKour course. First you climb a angled wall up 9.5 meters. They you shimmy along the edge of a 3.5 meter long wal

Svet_ta [14]

The average speed would be 0.65 m/s, therefore the correct option is (A).

The average speed is calculated by the formula

Average speed= (total distance/ total time)

The total distance of the trip=9.5+3.5+15=28 m

The total time of trip=43 sec

Therefore the average speed=28/43=0.65 m/s.

8 0

3 years ago

ANSWER IN LESS THAN A MIN!! EASY!​

ANSWER IN LESS THAN A MIN!! EASY!