Question

Denial cycled at 6 mph for 0.8 h. Then he jogged at 2 mph for

Answer 1

Deniel's average speed for the total

distance is 3.6 mph

Average speed is difined as the total distance travelled divided by the total time required to cover the distance. Mathematically, it is expressed as:

$Ave. Speed = \frac{Total distance }{Total time}$

To obtain the average speed of Daniel, we shall determine the distance travelled in each case. This is illustrated below:

Case 1:

Speed 1 (S₁) = 6 mph

Time 1 (t₁) = 0.8 h.

Distance 1 (D₁) =?

$Speed = \frac{Distance}{Time} \\\\S_{1} = \frac{D_{1}}{t_{1}} \\\\6 = \frac{D_{1}}{0.8}$

Cross multiply

D₁ = 6 × 0.8

D₁ = 4.8 mile

Case 2:

Speed 2 (S₂) = 2 mph

Time 2 (t₂) = 1.2 h.

Distance 2 (D₂) =?

$S_{2} = \frac{D_{2}}{t_{2}}\\\\2 = \frac{D_{2}}{1.2}$

Cross multiply

D₂ = 2 × 1.2

D₂ = 2.4 mile

Next, we shall determine the total time. This can be obtained as follow:

Time 1 (t₁) = 0.8 h.

Time 2 (t₂) = 1.2 h.

Total time (T) =?

T = t₁ + t₂

T = 0.8 + 1.2

T = 2 h

Next, we shall determine the total distance. This can be obtained as follow:

Distance 1 (D₁) = 4.8 mile

Distance 2 (D₂) = 2.4 mile

Total distance (D) =?

D = D₁ + D₂

D = 4.8 + 2.4

D = 7.2 mile

Finally, we shall determine the average speed of Daniel. This can be obtained as follow:

Total time = 2 h

Total distance  = 7.2 mile

Average speed =?

$Ave. speed = \frac{Total distance }{Total time} \\\\Ave. speed = \frac{7.2 }{2}$

Average speed = 3.6 mph

Therefore, the average speed of Daniel is 3.6 mph

Learn more: brainly.com/question/680492