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3 years ago

Denial cycled at 6 mph for 0.8 h. Then he jogged at 2 mph for

Physics

1 answer:

dexar [7]3 years ago

5 0

<h3>Deniel's average speed for the total</h3><h3>distance is 3.6 mph</h3>

Average speed is difined as the total distance travelled divided by the total time required to cover the distance. Mathematically, it is expressed as:

$Ave. Speed = \frac{Total distance }{Total time}$

To obtain the average speed of Daniel, we shall determine the distance travelled in each case. This is illustrated below:

Speed 1 (S₁) = 6 mph

Time 1 (t₁) = 0.8 h.

<h3>Distance 1 (D₁) =? </h3>

$Speed = \frac{Distance}{Time} \\\\S_{1} = \frac{D_{1}}{t_{1}} \\\\6 = \frac{D_{1}}{0.8}$

Cross multiply

D₁ = 6 × 0.8

Speed 2 (S₂) = 2 mph

Time 2 (t₂) = 1.2 h.

<h3>Distance 2 (D₂) =? </h3>

$S_{2} = \frac{D_{2}}{t_{2}}\\\\2 = \frac{D_{2}}{1.2}$

Cross multiply

D₂ = 2 × 1.2

Next, we shall determine the total time. This can be obtained as follow:

Time 1 (t₁) = 0.8 h.

Time 2 (t₂) = 1.2 h.

<h3>Total time (T) =? </h3>

T = t₁ + t₂

T = 0.8 + 1.2

Next, we shall determine the total distance. This can be obtained as follow:

Distance 1 (D₁) = 4.8 mile

Distance 2 (D₂) = 2.4 mile

<h3>Total distance (D) =?</h3>

D = D₁ + D₂

D = 4.8 + 2.4

Finally, we shall determine the average speed of Daniel. This can be obtained as follow:

Total time = 2 h

Total distance = 7.2 mile

<h3>Average speed =?</h3>

$Ave. speed = \frac{Total distance }{Total time} \\\\Ave. speed = \frac{7.2 }{2}$

<h3>Average speed = 3.6 mph</h3><h3 />

Therefore, the average speed of Daniel is 3.6 mph

Learn more: brainly.com/question/680492

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