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3 years ago

What is the answer please?

Mathematics

1 answer:

Marina CMI [18]3 years ago

8 0

Answer:

The one you are on, f(x+2)+4

Step-by-step explanation:

First, we can see by the 0 point that it is just moved up by 4 and not left or right any, so we want to see how it has changed without the +4.

in g(x) the x changes by two, 0 to 2, and the y changes by one, 4 to 5.

Hopefully you can tell what the function being manipulated is. It is x^3 so if we write that instead of f(x) in the answers the first one for instance would be (x/3)^3-4. (let me know if that doesn't make sense)

SInce we already know it's being moved up by 4, we know it's one of those with +4 at the end. It's easy enough to guess and check, but the process to find the answer is pretty easy. We also know that at 2, the change is 1. So without the +4 at the end, what would let us change 8 to 1? dividing it by 8, which is also 2^3. so that means (2/2)^3. So the answer is we want f(x/2) witht he +4 at the end.

Hopefully that made sense, I'd be happy to explain further if you need though

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Need help with both of these please!! ASAP

Alik [6]

x = 1

Answer:

$m\angle XVW = 100\degree$

Step-by-step explanation:

In the first figure, FP is the bisector of $\angle DFE$

$\therefore m\angle 1 = m\angle 2\\\therefore 44x + 1 = 46x - 1\\\therefore 1 + 1 = 46x - 44x\\\therefore 2 = 2x\\\therefore \frac{2}{2} = x \\\huge \red {\boxed {\therefore x = 1}}$

In the second figure, VP is the bisector of $\angle XVW$

$\therefore m\angle 1 = m\angle 2\\\therefore 12x + 2 = 11x +6\\\therefore 12x - 11x = 6 - 2\\\therefore x = 4\\\because m\angle XVW = m\angle1 + m\angle 2\\\therefore m\angle XVW = 12x + 2 + 11x +6\\\therefore m\angle XVW = 23x + 8\\\therefore m\angle XVW = 23\times 4+ 8\\\therefore m\angle XVW = 92+ 8\\\huge \purple {\boxed {\therefore m\angle XVW = 100\degree}} \\$

8 0

3 years ago

Write this ratio in one other way 7/13

Ierofanga [76]

You can write this ratio in two other ways:

7 to 13

7 : 13

5 0

3 years ago

Read 2 more answers

Solve using the elimination method:<br> X-3y=7<br> 3x + 3y=9

sergij07 [2.7K]

Answer:

$x=4\\\\y=-1$

Step-by-step explanation:

Given Equation:

$x-3y=7$ Equation:1

$3x + 3y=9$ Equation:2

Dividing Equation:2 by '3' both the sides:

$x+y=3$

or $x=3-y$ Equation:3

Putting the vale of 'x' in Equation:1

$x-3y=7$

$(3-y)-3y=7\\\\3-y-3y=7\\\\3-4y=7\\\\$

Subtracting '3' both sides

$-4y=7-3\\\\-4y=4$

$y=\frac{4}{-4}$

$y=-1$

Putting value of 'y' in Equation:3

$x=3-y$

$x=3-(-1)\\\\x=3+1\\\\x=4$

The solution of the equations is :

$x=4\\\\y=-1$

7 0

4 years ago

Help if you want brianleist!! :) uhm don't mind update- NO LINkS- Thank you to those who help! :)

marta [7]

The answer would be 2 I’m pretty sure

3 0

3 years ago

Read 2 more answers

If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?

Keith_Richards [23]

$\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}$

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

$\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}$

so, the domain is all real numbers EXCEPT that one.

4 0

3 years ago