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3 years ago

5

Add $50 million and 179.7 billion,

2 answers:

d1i1m1o1n [39]3 years ago

6 0

50 million + 179.7 Billion = 179.75 billion.

I would give 2 billion to different charties than probably get a nice house, nice car, Playstation 5 (obvi) than I would give the rest out on poor people and my family and friends.

What would u do?

makvit [3.9K]3 years ago

3 0

The answer must be between 20 and 5000 characters

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What is the range of the function shown below?

Ivenika [448]

Answer:

Step-by-step explanation:

{ - 9, - 4, - 1}

5 0

3 years ago

Are you able to write?

Volgvan

Answer:

Well isn't anyone able to write?

3 0

3 years ago

Read 2 more answers

Write in vertex form<br> f(x)=x^2+12x+34

svp [43]

Answer:

(-6, -2)

Step-by-step explanation:

$f(x) = {x}^{2} + 12x + 34$

$= f(x) = {1x}^{2} + 12x + 34$

= a = 1, b = 12

$= x = - \frac{12}{2 \times 1}$

$= x = - \frac{12}{2}$

= x = -6

$= f(x) = {x}^{2} + 12x + 34.. = - 6$

$= f( - 6) = - 2$

= (-6, -2)

8 0

2 years ago

Without a calculator how would you solve this?

mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

$\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6$

$=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}$

$\bigstar\ (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}$

$\bigstar\ \bigstar\ (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}$

$\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702$

$\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6$

$0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0$

$\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0$

$\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702$

8 0

2 years ago

Write the sum using summation notation, assuming the suggested pattern continues.

Lina20 [59]

<u>ANSWER</u>

$\sum _{n = 1} ^{18} (6n - 15)$

<u>EXPLANATION</u>

The given series

$- 9 - 3 + 3 + 9 + ... + 81$

This is an arithmetic series with a common difference of

$d = - 3 - - 9 = 6$

The first term of the series is:

$a_1 = - 9$

The general term is given by:

$a_n =a_1 + d(n - 1)$

$a_n = - 9+ 6(n - 1)$

$a_n = - 9+ 6n - 6$

$a_n =6n - 15$

The last term is 81

We can use this to determine the number of terms in the series.

$81=6n - 15$

$81 + 15=6n$

$6n = 96$

$n = \frac{96}{6} = 16$

The summation notation is:

$\sum _{n = 1} ^{18} (6n - 15)$

4 0

3 years ago